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avanturin [10]
1 year ago
5

What is the mode of 250,100,75,200,150,100

Mathematics
2 answers:
Nataly_w [17]1 year ago
4 0

Answer:

100

Step-by-step explanation:

because 100 showed twice more then the others

Paha777 [63]1 year ago
4 0

Answer:

To find the mode of this question. You look for the number that showed up the most out of the values given. In this case you answer is 100.

Step-by-step explanation:

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The diameter is 12 inches. What is the area? What do I do to solve it please help!
SashulF [63]

Answer:

113.04 sq. in.

Step-by-step explanation:

If the diameter of the circle is 12", then the radius is 6" (half the diameter), and the area "A" is (approximately) 3.14 * 6^2. The calculation is approximate because 3.14 is a rounded value for pi.

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3 years ago
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Y=-x-4
aliina [53]

Answer:

(-4 , 0)

Step-by-step explanation:

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3 years ago
Jill uses some of her honey to make lotion if each bottle of lotion requires 1/4 gallon and she uses a total of 3 gallons how ma
AURORKA [14]
So, we need to count up 1/4 each time till we get to 3.

1/4, 2/4, 3/4, 1, 1 1/4, 1 2/4, 1 3/4, 2, 2 1/4, 2 2/4, 2 3/4, 3.

Now, let's count how many times we counted to get to 3.

12.

So, Jill used 12 bottles of lotion.

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3 years ago
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25. A sequence of positive integers with 2020 terms is called an FT sequence if each term
lana66690 [7]

Answer:

The first term in the sequence is odd-valued and so there are m choices for it.2020 Gauss Contest Solutions Page 19

The second term in the sequence is even-valued and so there are m − 1 choices for it.

Thus, there are a total of m × (m − 1) FT sequences that begin with an odd-valued term

followed by an even-valued term.

Finally, we consider the FT sequences that begin with an even-valued term followed by an

odd-valued term (Parity #4).

Again, there are exactly twice as many odd-valued terms as there are even-valued terms in the

first 2019 terms (since the pattern repeats even, odd, odd).

However in this case, the 2020th term is even and so there are fewer than twice as many odd valued terms as there are even-valued terms.

Thus, there are m2 + m × (m − 1) FT sequences that satisfy the required conditions.

Since there are 2415 such FT sequences, we may solve m2 + m × (m − 1) = 2415 by trial and

error.

Evaluating m2 + m × (m − 1) when m = 30, we get 302 + 30 × 29 = 1770, and so m is greater

than 30.

When m = 33, we get 332 + 33 × 32 = 2145.

When m = 34, we get 342 + 34 × 33 = 2278.

When m = 35, we get 352 + 35 × 34 = 2415, as required.

Answer: (D)

Step-by-step explanation:

8 0
3 years ago
My'chael has read 120 pages, which is 45% of a book. How many<br> pages are in the book?
Mars2501 [29]

Answer:

266.67

Step-by-step explanation:

120=.45(x)

x=266.67

7 0
2 years ago
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