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Fofino [41]
3 years ago
14

What is the vertices of hexagon​

Mathematics
2 answers:
nata0808 [166]3 years ago
5 0
Number of vertices of hexagon is 6
andre [41]3 years ago
3 0

Answer:

A Hexagon has 6 sides so 6 Vertices

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Find the particular solution to y'=2sin(x) given the general solution is y=C-2cos(x) and the initial condition y(pi/3)=1
mezya [45]

ANSWER

The particular solution is:

y=2-2 \cos(x)

EXPLANATION

The given Ordinary Differential Equation is

y'=2 \sin(x)

The general solution to this Differential equation is:

y=C-2 \cos(x)

To find the particular solution, we need to apply the initial conditions (ICs)

y( \frac{\pi}{3} ) = 1

This implies that;

C-2 \cos( \frac{\pi}{3} ) = 1

C-2( \frac{1}{2} )= 1

C-1= 1

C= 1 + 1 = 2

Hence the particular solution is

y=2-2 \cos(x)

4 0
3 years ago
Write the contrapositive and the converse of the following conditional
Lunna [17]

The contrapositive statement are:

  • If the lake is frozen, then it isn't cold.
  • If Solomon is happy, then  he isn't healthy.
  • If Tigist  does not take a walk, then it will not rain

<h3>What is the converse statement?</h3>

The  converse statement are:

  • If the late is frozen, then it is cold.
  • If Solomon is happy, then he is healthy.
  • If Tigist Tigist  does not take a walk, then it will rain.

Note that the converse of a statement is created by the act of switching the hypothesis given and also the conclusion.

Therefore, The contrapositive statement are

  • If the lake is frozen, then it isn't cold.
  • If Solomon is happy, then  he isn't healthy.
  • If Tigist  does not take a walk, then it will not rain

Learn more about contrapositive statement  from

brainly.com/question/1713053

#SPJ1

6 0
2 years ago
Read 2 more answers
Given: j(x) = x2 - 2x + 1
kicyunya [14]

Answer:

{1, 0, 16}

Step-by-step explanation:

given..

j(x) = x^2-2x+1

put all given values of domain (1,0 and 5 ) in the equation..

the values you get are range of the function

4 0
3 years ago
Read 2 more answers
18. cos t(sec t - cos t)
Margarita [4]
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8 0
3 years ago
An oval track is made by erecting semicircles on each end of a 60m by 120m rectangle. Find the length of the track and the area
vodomira [7]
Refer to the figure shown below.

Because the question states that the semi circles are at the ends of the rectangle, each semicircle has a radius of 30 m.

The circumference of the oval is
2π(30) + 2*120 = 60π + 240 m = 428.5 m

The area of the oval is 
π(30²) + 60*120 = 900π + 7200 m² = 1.0027 x 10⁴ m²

Note:
If the semi circles are placed on the 120-m sides of the rectangle, then similar calculations yield:
Circumference = 120π + 120 m = 497 m
Area = 3600π + 7200 m² = 1.851 x 10⁴ m²

Answer:
If the semi circles are placed on the 60-m sides of the rectangle, then
Circumference = 60π + 240 m, or 428.5 m
Area = 900π + 7200 m², or 1.0027 x 10⁴ m²

if the semi circles are placed on the 120-m sides of the rectangle, then
Circumference = 120π + 120 m, or 497 m
Area = 3600π + 7500 m², or 1.851 x 10⁴ m²


3 0
3 years ago
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