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ki77a [65]
2 years ago
12

What’s the radius of center (-2,1) and contains the point (2,-1)

Mathematics
1 answer:
solniwko [45]2 years ago
8 0
<h2>Radius of a Circle Given Center and Point</h2>

To find the radius of a circle when we're given the coordinates of its center and a point it contains, we can use the following formula for distance:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2

  • (x_1,y_1) is one point and (x_2,y_2) is another

<h2>Solving the Question</h2>

We're given:

  • Center: (-2,1)
  • Point: (2,-1)

Plug these given points into the formula for distance:

d=\sqrt{(2-(-2))^2+(-1-1)^2}\\d=\sqrt{(2+2)^2+(-1-1)^2}\\d=\sqrt{(4)^2+(-2)^2}\\d=\sqrt{16+4}\\d=\sqrt{20}\\d\approx4.47

<h2>Answer</h2>

Therefore, the radius of the circle is \sqrt{20} units, or approximately 4.47 units.

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Answer:

Gym A

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A linear relationship is a relationship of the form y = mx + b, where y and x are the linear variables, m is the rate of change and b is the value of y when x = 0.

Gym A:

Let x represent the month and y represent the total cost for the gym. From the table, we can represent the values in the form (x, y) as (1,70), (2, 90) and (3, 110). We can find the relationship between x and y using the formula:

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\Let \ us\ use\ the\ points\  (1,70)\ and\ (3,110),hence:\\\\y-70=\frac{110-70}{3-1}(x-1)\\\\y-70=20(x-1)\\\\y=20x-20+70 \\\\y=20x+50\\\\For\ 10\ months(i.e.\ x=10):\\\\y=20x+50\\\\y=20(10)+50\\\\y=\$250

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We can represent the values from the table as (1,55), (2, 80) and (3, 105). We can find the relationship between x and y using the formula:

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\Let \ us\ use\ the\ points\  (1,55)\ and\ (3,105),hence:\\\\y-55=\frac{105-55}{3-1}(x-1)\\\\y-55=25(x-1)\\\\y=25x-25+55 \\\\y=25x+30\\\\For\ 10\ months(i.e.\ x=10):\\\\y=25x+30\\\\y=25(10)+30\\\\y=\$28 0

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