Answer:
A) 4 students
B) 32.5%
C) 19/40
Step-by-step explanation:
Using set notation to solve the problem with universal set n(U) = 40
Let n(A) be the number of students that pass account
n(E) be the number of students that pass economics
n(M) be the number of students that pass mathematics
n(AUEUM)' be number of students that failed in all the 3 subjects.
n(AUEUM) be number of students that pass in all the 3 subjects.
n(U) = n(AUEUM)+ n(AUEUM)'
Find the remaining solution in the attachment
I can give you are summary of how to do it. UK geometry is somewhat different to US with regard to symbols used and names.
You need to prove that the 2 triangles BCE and ADE are congruent and then you can say that the sides are also congruent:- Sides BC and AD are equal (opposite sides of a parallelogram) Also < CBE = <ADE ( alternate angles) and < BCE = EAD ( alternate angles) So the triangles are congruent by 2 angles and the corresponding side, ( I think that would be ASA in the US).
1.
X = 0
2x + 1 = 0
X = 0
X = - ½ (Because we brought the numbers from one side to the other)
2.
Not sure for number 2.
Answer:
so it's
3/7m<21
and we devide both sides of the inequality.
/2r-1\>7
And we can rewrite it as a compound Inequality
2r-1<7 (or) 2r-1>7 Ima give u the enter
[r<-3 or r>4 I guess it's like this❕
2.1
If the number was 2.15, you would round to 2.2 because any place that is 5 or greater rounds up and any place less than 5 rounds down.
.1 is the tenths place
.11 is the one hundredths places