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ExtremeBDS [4]
3 years ago
6

How do you factor?: 4x^2 + 12x + 9 (Please show steps)

Mathematics
1 answer:
Bumek [7]3 years ago
8 0

Answer: Rewrite 4x squared as (2x) squared

(2x) squared +12x + 9

rewrite 9 as (3) squared

Check the middle term by multiplying

2ab and compare this result with the middle term in the original expression.

2ab = 2 x (2x) x 3

Simplify 2ab = 12x, then factor using the perfect square trinomial rule. A sqaured + 2ab + b squared = (a + b) squared

A = 2x and B = 3

So your answer is

(2x + 3) squared!

sorry its so long

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What’s the area of the sector=
N76 [4]

Answer:

Step-by-step explanation:

(\pi)\left(\frac{60}{360} \right)(9^{2})=\boxed{13.5\pi}

3 0
2 years ago
Is this relation a function? Justify your answer. URGENT PLEASE HELP BRAINLIEST!!!!!!!!
Papessa [141]

Answer:

A.  No, because two points with the same x-value have different y-values.

Step-by-step explanation:

No, because it doesn't pass the Vertical Line Test:

A.  No, because two points with the same x-value have different y-values.

6 0
3 years ago
How can I simplify/rewrite the 1st(top) equation into the 2nd(Botton),please show a step by step solution.​
Vaselesa [24]

Answer:

see below

Step-by-step explanation:

-2(4 - \frac{x}{2} )^{5} + C

Think of the above as:

  -\frac{2}{1} * (\frac{8}{2} - \frac{x}{2} )^{5} + C

= -\frac{2}{1} * \frac{(8 - x)^{5}}{2^{5}}  + C

= -\frac{2}{1} * \frac{(8 - x)^{5}}{32}  + C

= -\frac{1}{1} * \frac{(8 - x)^{5}}{16}  + C

=   \frac{-1(8 - x)^{5}}{16}  + C

=   \frac{(-8 + x)^{5}}{16}  + C

Can flip it around to be...

\frac{(x - 8)^{5}}{16}  + C

4 0
3 years ago
Find three consecutive odd integers so that the sum of twice the first, the second
netineya [11]

Answer: 23, 25, 27

Step-by-step explanation:

Let the 3 consecutive odd numbers be x, x+2 and x+4.

So

2x+(x+2)+3(x+4)=152

2x + x + 2 + 3x + 12 = 152

6x+14=152

6x = 152 - 14

x=138/6

x=23

So, the numbers are 23, 25 and 27.

7 0
3 years ago
What is the square root of 5x^2 = 300
vesna_86 [32]

So, values of x are: x=2\sqrt{15},\,\,x=-2\sqrt{15}

Step-by-step explanation:

We need to find the square root of 5x^2 = 300

Writing in mathematical form:

5x^2=300

Divide both sides by 5

\frac{5x^2}{5}=\frac{300}{5}

x^2=60

Taking square root on both sides

\sqrt{x^2}=\sqrt{60}

x=\pm (\sqrt{2\times 2\times 3\times 5})

x=\pm (\sqrt{2^2 \times 3\times 5})

x=\pm (2\sqrt{3\times 5})

x=\pm (2\sqrt{15})

x=2\sqrt{15},\,\,x=-2\sqrt{15}

So, values of x are: x=2\sqrt{15},\,\,x=-2\sqrt{15}

Keywords: Square root

Learn more about square root at:

  • brainly.com/question/3511750
  • brainly.com/question/4034547

#learnwithBrainly

7 0
4 years ago
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