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kaheart [24]
2 years ago
7

Consider the right triangle 8 in. 5 in. x what is x

Mathematics
1 answer:
kirill [66]2 years ago
3 0

x²= 8²-5²

=39

x=V39

..........

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Can u help me ASAP!!!
Rom4ik [11]
Can be reduced to 1/3
8 0
3 years ago
90 POINTS!!!!! Given: KLIJ inscr. in k(O),m∠K = 64°, measure of arc LI = 69°, measure of arc IJ = 59°, measure of arc KJ =97°
Kay [80]

In any cyclic quadrilateral, angles opposite one another are supplementary, meaning

m\angle K+m\angle I=m\angle L+m\angle J=180^\circ

and given that \boxed{m\angle K=64^\circ}, we have \boxed{m\angle I=116^\circ}.

By the inscribed angle theorem,

m\angle JLK=\dfrac12m\widehat{KJ}

m\angle ILJ=\dfrac12m\widehat{IJ}

and since

m\angle L=m\angle JLK+m\angle ILJ

we have

m\angle L=\dfrac{97^\circ+59^\circ}2\implies\boxed{m\angle L=78^\circ}

and it follows that

m\angle J=180^\circ-m\angle L\implies\boxed{m\angle J=102^\circ}

5 0
3 years ago
Write the expression 3 +2 x 20
prohojiy [21]
3+2 x20
3+2=5
5x20=
100
Hope this helped.
3 0
3 years ago
Read 2 more answers
An experiment consists of choosing objects without regards to order. Determine the size of the sample space when you choose the
sdas [7]

Answer:

a

    n=  75, 582

b

  n=    2300

c

  n =   253

Step-by-step explanation:

     Generally the size of the sample sample space is  mathematically represented as

           n  =   \left N } \atop {}} \right.  C_r

Where   N is the total number of objects available and  r is the  number of objects to be selected

    So  for  a,  where N = 19  and r = 8  

         n  =   \left 19 } \atop {}} \right.  C_8 =  \frac{19 !}{(19 - 8 )! 8!}

                           =     \frac{19 *18 *17 *16 *15 *14 *13 *12 *11! }{11 ! \ 8!}

                           n=  75, 582

    For  b  Where  N  = 25 and  r  =  3

           n  =   \left 25 } \atop {}} \right.  C_3 =  \frac{25 !}{(19 - 3 )! 3!}

                             =     \frac{25 *24 *23 *22 !  }{22 ! \ 3!}

                             n=    2300

   For  c  Where  N  = 23 and  r  =  2

            n  =   \left 23 } \atop {}} \right.  C_2 =  \frac{23 !}{(23 - 2 )! 2!}

                              =     \frac{23 *22 *21!  }{21 ! \ 3!}

                              n =   253

4 0
4 years ago
To obtain an average (arithmetic mean) of exactly 2/3, what fraction must be added to 1/6, 1/2, and 1/3?
ollegr [7]

Answer:

D. 5/3

Step-by-step explanation:

\frac{1/6+1/2+1/3+x}{4} =2/3

1/6+1/2+1/3+x=8/3

x=8/3-1/6-1/2-1/3

x=8/3-1/6-3/6-2/6

x=8/3-6/6

x=16/6-6/6=10/6

simplified

x=5/3

Hope this helps

3 0
2 years ago
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