3 years ago

How do you do question 19?

Mathematics

1 answer:

nika2105 [10]3 years ago

4 0

The answer is B, 6hrs.

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Which ordered pairs lie on the graph of the exponential function f (x) = 3(0.2)^x

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The ordered pairs which lie on the graph of the exponential function, f(x) = 3(0.2)^x is; Choice A; (0, 3).

<h3>Ordered pair Solution;</h3>

The given exponential function is;

f (x) = 3(0.2)^x

By testing all values; Only the pair; (0, 3) is a solution to the graph of the exponential given.

By testing;

f (0) = 3(0.2)⁰.

Where, (0.2)⁰ = 1 (from indices).

f(0) = 3 × 1 = 3.

Read more on ordered pairs;

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ANSWER

See below

EXPLANATION

Given

$f(x) = \frac{ {x}- 9 }{x + 5}$

and

$g(x) = \frac{ - 5x - 9}{x - 1}$

$(f \circ \: g)(x)= \frac{ (\frac{ - 5x - 9}{x - 1})- 9 }{(\frac{ - 5x - 9}{x - 1} )+ 5}$

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9 - 9(x - 1)}{x - 1}}{\frac{ - 5x - 9 + 5(x - 1)}{x - 1} }$

Expand:

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9 - 9x + 9}{x - 1}}{\frac{ - 5x - 9 + 5x - 5}{x - 1} }$

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9x + 9 - 9}{x - 1}}{\frac{ - 5x + 5x - 5 - 9}{x - 1} }$

$(f \circ \: g)(x)= \frac{ \frac{ - 14x }{x - 1}}{\frac{ -14}{x - 1} }$

Since the denominators are the same, they will cancel out,

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