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sergeinik [125]
3 years ago
11

How do you do question 19?

Mathematics
1 answer:
nika2105 [10]3 years ago
4 0

The answer is B, 6hrs.

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Which ordered pairs lie on the graph of the exponential function f (x) = 3(0.2)^x
photoshop1234 [79]

The ordered pairs which lie on the graph of the exponential function, f(x) = 3(0.2)^x is; Choice A; (0, 3).

<h3>Ordered pair Solution;</h3>

The given exponential function is;

  • f (x) = 3(0.2)^x

By testing all values; Only the pair; (0, 3) is a solution to the graph of the exponential given.

By testing;

  • f (0) = 3(0.2)⁰.

  • Where, (0.2)⁰ = 1 (from indices).

  • f(0) = 3 × 1 = 3.

Read more on ordered pairs;

brainly.com/question/5754926

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Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x.
charle [14.2K]

ANSWER

See below

EXPLANATION

Given

f(x) =  \frac{ {x}- 9 }{x + 5}

and

g(x) =   \frac{ - 5x - 9}{x - 1}

(f \circ \: g)(x)=  \frac{ (\frac{ - 5x - 9}{x - 1})- 9 }{(\frac{ - 5x - 9}{x - 1} )+ 5}

(f \circ \: g)(x)=  \frac{ \frac{ - 5x - 9 - 9(x - 1)}{x - 1}}{\frac{ - 5x - 9 + 5(x - 1)}{x - 1} }

Expand:

(f \circ \: g)(x)=  \frac{ \frac{ - 5x - 9 - 9x  + 9}{x - 1}}{\frac{ - 5x - 9 + 5x - 5}{x - 1} }

(f \circ \: g)(x)=  \frac{ \frac{ - 5x - 9x  + 9 - 9}{x - 1}}{\frac{ - 5x + 5x - 5 - 9}{x - 1} }

(f \circ \: g)(x)=  \frac{ \frac{ - 14x }{x - 1}}{\frac{ -14}{x - 1} }

Since the denominators are the same, they will cancel out,

(f \circ \: g)(x)= \frac{ - 14x}{ - 14}  = x

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The two polygons are similar. Find the measure of angle U.<br> 120°<br><br> 185°
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