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2 years ago

Help helphelp helpe hwlp hwlp

Mathematics

2 answers:

VashaNatasha [74]2 years ago

5 0

Answer:

0.6

Step-by-step explanation:

You count how many pieces there are in total, and then you subtract the blue pieces from the total which is 3. Then you need to convert 5/8 into a decimal.

NeTakaya2 years ago

4 0

0.6 is the answer. Your welcome

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A clothing store is selling T-shirts at 2 for $15. If Michael purchases 8 T-shirts, how much money will he spend?

deff fn [24]

Answer:

$60

Step-by-step explanation:

2 T-shirts = $15

Longer version

15/2 = $7.50

1 T- shirt = $7.50

7.50*8 = $60

Short version

2 T-shirts = $15

bought 8 so 8/2 = 4

4*15= 60

8 0

2 years ago

A group of students is investigating how the addition of salt impacts the floatation of an egg in water. Four identical cups wer

oksano4ka [1.4K]

Cup one is the cup do to there being no salt

3 0

3 years ago

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A common blood test performed on pregnant women to screen for chromosome abnormalities in the fetus measures the human chorionic

goldfiish [28.3K]

Answer:

(a) The proportion of women who are tested, get a negative test result is 0.82.

(b) The proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

Step-by-step explanation:

The Bayes' theorem states that the conditional probability of an event E $_{i}$ , of the sample space S, given that another event A has already occurred is:

$P(E_{i}|A)=\frac{P(A|E_{i})P(E_{i})}{\sum\liits^{n}_{i=1}{P(A|E_{i})P(E_{i})}}$

The law of total probability states that, if events E₁, E₂, E₃... are parts of a sample space then for any event A,

$P(A)=\sum\limits^{n}_{i=1}{P(A|B_{i})P(B_{i})}$

Denote the events as follows:

X = fetus have a chromosome abnormality.

Y = the test is positive

The information provided is:

$P(X)=0.04\\P(Y|X)=0.90\\P(Y^{c}|X^{c})=0.85$

Using the above the probabilities compute the remaining values as follows:

$P(X^{c})=1-P(X)=1-0.04=0.96$

$P(Y^{c}|X)=1-P(Y|X)=1-0.90=0.10$

$P(Y|X^{c})=1-P(Y^{c}|X^{c})=1-0.85=0.15$

(a)

Compute the probability of women who are tested negative as follows:

Use the law of total probability:

$P(Y^{c})=P(Y^{c}|X)P(X)+P(Y^{c}|X^{c})P(X^{c})$

$=(0.10\times 0.04)+(0.85\times 0.96)\\=0.004+0.816\\=0.82$

Thus, the proportion of women who are tested, get a negative test result is 0.82.

(b)

Compute the value of P (X|Y) as follows:

Use the Bayes' theorem:

$P(X|Y)=\frac{P(Y|X)P(X)}{P(Y|X)P(X)+P(Y|X^{c})P(X^{c})}$

$=\frac{(0.90\times 0.04)}{(0.90\times 0.04)+(0.15\times 0.96)}$

$=0.20$

Thus, the proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

6 0

3 years ago

Please show work too I really need help

kumpel [21]

Answer:

i really really like ya cut g

Step-by-step explanation:

3 0

3 years ago

The larger leg of a right triangle is 3cm longer than its smaller leg. The hypotenuse is 6cm longer than the smaller leg. how ma

Natalka [10]

$b=a+3\\
c=a+6\\
a^2+b^2=c^2\\\\
a^2+(a+3)^2=(a+6)^2\\
a^2+a^2+6a+9=a^2+12a+36\\
a^2-6a-27=0\\
a^2-9a+3a-27=0\\
a(a-9)+3(a-9)=0\\
(a+3)(a-9)=0\\
a=-3 \vee a=9\\
$

The length can't be negative, so the answer is 9 cm.

5 0

3 years ago

Read 2 more answers