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8090 [49]
2 years ago
9

Help helphelp helpe hwlp hwlp

Mathematics
2 answers:
VashaNatasha [74]2 years ago
5 0

Answer:

0.6

Step-by-step explanation:

You count how many pieces there are in total, and then you subtract the blue pieces from the total which is 3.  Then you need to convert 5/8 into a decimal.

NeTakaya2 years ago
4 0
0.6 is the answer. Your welcome
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Does this graph represent a function? Why or why not?
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It’s D because no lines overlap so it passes the vertical line test

Step-by-step explanation:

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3 years ago
Anyone can do this please if you can do all of it of you can I'm really bad at math​
Vilka [71]
Im Gonna Do 14 And 15.

14:
3/4 (9/12) + 1/3 (4/12) = 13/12
4/5 (16/20) - 1/4 (5/20) = 11/20

15:
-15 < -6
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Hope This Helps!
7 0
3 years ago
How many factors does the following term have -9xyz
madreJ [45]

Answer:

4

Step-by-step explanation:

3 0
3 years ago
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Three multiplied by a number g
Leviafan [203]
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3 years ago
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Determine whether the set of vectors is a basis for ℛ3. Given the set of vectors , decide which of the following statements is t
schepotkina [342]

Answer:

(A) Set A is linearly independent and spans R^3. Set is a basis for R^3.

Step-by-Step Explanation

<u>Definition (Linear Independence)</u>

A set of vectors is said to be linearly independent if at least one of the vectors can be written as a linear combination of the others. The identity matrix is linearly independent.

<u>Definition (Span of a Set of Vectors)</u>

The Span of a set of vectors is the set of all linear combinations of the vectors.

<u>Definition (A Basis of a Subspace).</u>

A subset B of a vector space V is called a basis if: (1)B is linearly independent, and; (2) B is a spanning set of V.

Given the set of vectors  A= \left(\begin{array}{[c][c][c][c]}1 & 0 & 0 & 0\\ 0 & 1 & 0 & 1\\ 0 & 0 & 1 & 1\end{array} \right) , we are to decide which of the given statements is true:

In Matrix A= \left(\begin{array}{[c][c][c][c]}(1) & 0 & 0 & 0\\ 0 & (1) & 0 & 1\\ 0 & 0 & (1) & 1\end{array} \right) , the circled numbers are the pivots. There are 3 pivots in this case. By the theorem that The Row Rank=Column Rank of a Matrix, the column rank of A is 3. Thus there are 3 linearly independent columns of A and one linearly dependent column. R^3 has a dimension of 3, thus any 3 linearly independent vectors will span it. We conclude thus that the columns of A spans R^3.

Therefore Set A is linearly independent and spans R^3. Thus it is basis for R^3.

8 0
3 years ago
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