All categories

2 years ago

Help helphelp helpe hwlp hwlp

Mathematics

2 answers:

VashaNatasha [74]2 years ago

5 0

Answer:

0.6

Step-by-step explanation:

You count how many pieces there are in total, and then you subtract the blue pieces from the total which is 3. Then you need to convert 5/8 into a decimal.

NeTakaya2 years ago

4 0

0.6 is the answer. Your welcome

You might be interested in

Charlie is flying a kite one afternoon and steps on the end of the string to have his

Butoxors [25]

Answer:

roubd it to 20 and you will get 679.90

7 0

2 years ago

7. A=15; b= (blank); c= 17

kondor19780726 [428]

Answer:b is 16

Step-by-step explanation:a is 15 and c is 17. So what comes in between those numbers, exactly 16

6 0

2 years ago

Order of the set of numbers from least to greatest : Square root of 64, 8 1/7,8.14...,15/2 please help

KIM [24]

Answer:

15 /2 , Square root of 64, 8.14, 8 1/7

4 0

2 years ago

Suppose that in a random sample of size 200, standard deviation of the sampling distribution of the sample mean 0.08. researcher

sertanlavr [38]

Answer:

400

Step-by-step explanation:

The computation of the sample size needed is shown below:

Since at the sample size of 200 there is a standard deviation of 0.08

But when the standard deviation is 0.04 so the sample size is 400

As sample standard deviation would be inversely proportional to the square root of the sample size

7 0

3 years ago

A national grocery store chain wants to test the difference in the average weight of turkeys sold in Detroit and the average wei

Arte-miy333 [17]

Answer:

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

The null hypothesis is accepted .

Assume the population variances are approximately the same

Step-by-step explanation:

Explanation:-

Given data a random sample of 20 turkeys sold at the chain's stores in Detroit yielded a sample mean of 17.53 pounds, with a sample standard deviation of 3.2 pounds

The first sample size 'n₁'= 20

mean of the first sample 'x₁⁻'= 17.53 pounds

standard deviation of first sample S₁ = 3.2 pounds

Given data a random sample of 24 turkeys sold at the chain's stores in Charlotte yielded a sample mean of 14.89 pounds, with a sample standard deviation of 2.7 pounds

The second sample size n₂ = 24

mean of the second sample "x₂⁻"= 14.89 pounds

standard deviation of second sample S₂ = 2.7 pounds

Null hypothesis:-H₀: The Population Variance are approximately same

Alternatively hypothesis: H₁:The Population Variance are approximately same

Level of significance ∝ =0.05

Degrees of freedom ν = n₁ +n₂ -2 =20+24-2 = 42

Test statistic :-

$t = \frac{x^{-} _{1} - x_{2} }{\sqrt{S^2(\frac{1}{n_{1} } }+\frac{1}{n_{2} } }$

where $S^{2} = \frac{n_{1} S_{1} ^{2}+n_{2}S_{2} ^{2} }{n_{1} +n_{2} -2}$

$S^{2} = \frac{20X(3.2)^2+24X(2.7)^2}{20+24-2}$

substitute values and we get S² = 40.988

$t= \frac{17.53-14.89 }{\sqrt{40.988(\frac{1}{20} }+\frac{1}{24} )}$

t = 1.3622

Calculated value t = 1.3622

Tabulated value 't' = 2.081

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

Conclusion:-

The null hypothesis is accepted

Assume the population variances are approximately the same.

6 0

2 years ago