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3 years ago

Solve 3d/4-1/2=7 I need help I don't understand if someone one could help that would be great.

2 answers:

7 0

$\dfrac{3d}{4}-\dfrac{1}{2}=7\ \ \ \ |\cdot4\\\\\not4^1\cdot\dfrac{3d}{\not4_1}-\not4^2\cdot\dfrac{1}{\not2_1}=4\cdot7\\\\3d-2=28\ \ \ \ |+2\\\\3d=30\ \ \ \ |:3\\\\d=10$

noname [10]3 years ago

5 0

The three terms are 3d/4 and -1/2 and 7. Multiply each of these terms by 4. Why 4? This is the lowest common denominator (LCD) of the fractions. If we multiply all the terms by the LCD, then the denominators will cancel out. This will get rid of the fractions.

4 times 3d/4 = 3d

4 times -1/2 = -2

4 times 7 = 28

After multiplying each term by 4, we end up with the equation 3d - 2 = 28

Let's solve for d

------------------------

3d - 2 = 28

3d-2 + 2 = 28+2 .... add 2 to both sides

3d = 30

3d/3 = 30/3 .... divide both sides by 3

d = 10

------------------------

The final answer is d = 10

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Select all the expressions that have a value of 22 - 33 +29.

AysviL [449]

Answer:

B. and E.

Step-by-step explanation:

2^(2)-3^(3)+29 = 6

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3 years ago

What is x^2-1-3(2x-2)(x-2)

gayaneshka [121]

Answer:

=−5x2+18x−13

Step-by-step explanation:

Let's simplify step-by-step.

x2−1−3(2x−2)(x−2)

Distribute:

=x2+−1+−6x2+18x+−12

Combine Like Terms:

=x2+−1+−6x2+18x+−12

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Answer:

=−5x2+18x−13

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3 years ago

The line segment joining the points ( 3,-4) and (1,2) is trisected at the points P and Q . If the coordinates of P and Q are (p

sdas [7]

Answer:

P = 7/3 and q = 0

Step-by-step explanation:

The given parameters are;

The endpoints of the segment are, (3, -4) and (1, 2)

The points that trisect the given points are P and Q with coordinates (p, -2) and (5/3, q) respectively

Therefore, we have;

The first point of the trisection cuts 1/3 of the length from one point and the second point of the trisection cuts 2/3 of the length from the same point

The coordinates of P or Q = (3 - (3 - 1)/3, -4 - (-4 - 2)/3) = (7/3 , -2)

Therefore, given that the y-coordinate value of the derived point coincides with the y-coordinate value of the point P, (p, -2) and there is only one point with x = -2 on the line, we have that the coordinate of the point P is (p, -2) = (7/3 , -2)

∴ P = 7/3

Similarly we have the second point of the trisection, Q, given as follows;

We are already given the x-coordinate value of the point Q as the 5/3 in (5/3, q)

Point Q = (5/3, q) = (3 - 2×(3 - 1)/3, -4 - 2×(-4 - 2)/3) = (5/3 , 0)

Point Q = (5/3, q) = (5/3 , 0)

∴ q = 0.

3 0

3 years ago

I really need help with this one please

natka813 [3]

The distance from the sun is option 2 5.59 astronomical units.

Step-by-step explanation:

Step 1; To solve the question we need two variables. P which represents the number of years a planet takes to complete a revolution around the Sun. This is given as 13.2 years in the question so P = 13.2 years. The other variable is the distance between the planet and the sun in astronomical units. We need to determine the value of this using the given equation.

Step 2; So we have to calculate the value of 'a' in Kepler's equation. But the exponential power $\frac{3}{2}$ is on the variable we need to find so we multiply both the sides by an exponential power of $\frac{2}{3}$ to be able to calculate 'a'.

P = $a^{\frac{3}{2} }$ , $P^{\frac{2}{3} }$ = $a^{\frac{3}{2}*\frac{2}{3} }$ , $P^{\frac{2}{3} }$ = a, $13.2^{\frac{2}{3} }$ = a = 5.58533 astronomical units.