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3 years ago

301,251,769 to the nearest ten thousand

Mathematics

2 answers:

kondaur [170]3 years ago

8 0

It would be 301,250,000 I think

Levart [38]3 years ago

3 0

Answer:

301,250,000

I'm pretty sure that's it.

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kykrilka [37]

Answer:

Andre has the correct answer. When simplified his answer is equivalent to the original equation.

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3 years ago

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Seven increased by the product of two numbers

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Yu add the products of the two numbers by 7

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3 years ago

If $396 is invested at an interest rate of 13% per year and is compounded continuously, how much will the investment be worth in

Ipatiy [6.2K]

Answer:

$A=\$584.88$

Step-by-step explanation:

we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

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substitute in the formula above

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3 years ago

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natta225 [31]

Answer:

Step-by-step explanation:

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2 years ago

solve the problem related to population growth.A city had a population of 23,900 in 2007 and a population of 25,100 in 2012.(a)

Finger [1]

Solution

To find the exponential growth function, we apply the exponential growth formula which is

$N(t)=a(1+k)^t$

Where

$\begin{gathered} a\text{ is the }initial\text{ population} \\ k\text{ is the growth rate} \\ t\text{ is the number of time intervals} \end{gathered}$

Given that

$\begin{gathered} a=23,900 \\ N(5)=25,100 \\ t=2012-2007=5 \end{gathered}$

Substitute the variables into the exponential growth formula

$\begin{gathered} 25100=23900(1+k)^5 \\ \text{Divide both sides by 23,900} \\ \frac{25100}{23900}=\frac{23900(1+k)^5}{23900} \\ 1.05021=(1+k)^5^{} \\ \sqrt[5]{1.05021}=1+k \\ 1.00984=1+k \\ \text{Collect like terms} \\ k=1.00984-1 \\ k=0.00984 \end{gathered}$

Hence, the exponential growth function is