First and third, second can still be simplified.
Triangle A is the original triangle, and triangle A' is the image.
We need a pair of corresponding sides in the two triangles that are both labeled with lengths.
We see the side labeled 15.2 mm in triangle A', and we see the side labeled 3.8 mm in triangle A. These two sides are corresponding sides.
Divide the length of the side in the image by the length of the side in the original to find the scale factor.
(15.2 mm)/(3.8 mm) = 4
The scale factor is 4.
Step-by-step explanation:
2 things to remember for problems like this :
the sum of all angles in a triangle is always 180 degrees.
the law of sines :
a/sin(A) = b/sin(B) = c/sin(C) or upside-down (whatever fuss the situation better), with the sides being always opposite of the angles.
so, now for the given problems :
4.
x/sin(90) = 12/sin(29)
x/1 = x = 12/sin(29) = 24.75198408...
rounded x = 24.8
5.
the opposite angle of x is
180 - 90 - 16 = 74 degrees.
x/sin(74) = 37/sin(90) = 37
x = 37×sin(74) = 35.56668275...
rounded x = 35.6
6.
the opposite angle of x is
180 - 90 - 58 = 32 degrees.
x/sin(32) = 22/sin(58)
x = 22×sin(32)/sin(58) = 13.74712574...
rounded x = 13.7
7.
the opposite angle of 15 is
180 - 90 - 51 = 39 degrees.
x/sin(51) = 15/sin(39)
x = 15×sin(51)/sin(39) = 18.52345735...
rounded x = 18.5
