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Rainbow [258]
3 years ago
7

A line on the wall and a line on the floor are skew. always sometimes never

Mathematics
2 answers:
krok68 [10]3 years ago
6 0
They will never intersect nor be parallel.

Is this what you are asking? If they will always, sometimes, or never intersect?
KATRIN_1 [288]3 years ago
3 0
I believe they will sometimes be skew to the floor.
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Guyssssssss help me 10 points!!
zlopas [31]

Answer:

19

Step-by-step explanation:

the side is same as 57

what times 3 is 57?

57/3 is 19

AB is 19

pls vote me as brainliest!!!<3

8 0
3 years ago
Solve for k 4.5+1.5k=18−3k
sertanlavr [38]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{k = 3}}}}}

Step-by-step explanation:

\sf{4.5 + 1.5k = 18 - 3k}

Move 3k to left hand side and change it's sign

Similarly, move 4.5 to right hand side and change it's sign

\longrightarrow{ \sf{1.5k + 3k = 18 - 4.5}}

Collect like terms

\longrightarrow{ \sf{4.5k = 18 -  4.5}}

Subtract 4.5 from 18

\longrightarrow{ \sf{4.5k = 13.5}}

Divide both sides by 4.5

\longrightarrow{ \sf{ \frac{4.5k}{4.5}  =  \frac{13.5}{4.5} }}

Calculate

\longrightarrow{ \sf{k = 3}}

Hope I helped!

Best regards! :D

5 0
2 years ago
Read 2 more answers
Y &gt;x2-8x+17<br> Please help me !!!:((
Shalnov [3]
I hope this is the correct way to solve one of these.

first you need to know how the graph is so you consider y=x²-8x+17 (you might want to see the picture below to understand in a better way)

then you have to evaluate two points. one above the curve and one underneath the curve to see where y is greater than the curve. so let’s try for instance (0,0) and (4,2)
finally you must determine which points confirm that the statement is actually true. then you select the region for your solution :)

4 0
2 years ago
Fill in the blank: Type your answer in the box and then click "submit."
zepelin [54]
A way to write this would be:
100 - e = 42
5 0
3 years ago
What’s the correct answer for this?
Maurinko [17]

Answer:

B is correct

Step-by-step explanation:

Side ratio is 40/25 = 8/5

3 0
3 years ago
Read 2 more answers
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