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Sauron [17]
3 years ago
10

An arcade holds a game night. Of the 120 customers who visit during the game night, 30 customers are offered free games. What pe

rcent of the customers are not offered free games?
Mathematics
1 answer:
lilavasa [31]3 years ago
7 0

Answer:

75% of customers are not offered free games.

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A student takes an exam containing 1414 multiple choice questions. The probability of choosing a correct answer by knowledgeable
Readme [11.4K]

Answer:

0.0082 = 0.82% probability that he will pass

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the students guesses the correct answer, or he guesses the wrong answer. The probability of guessing the correct answer for a question is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 14, p = 0.3.

If the student makes knowledgeable guesses, what is the probability that he will pass?

He needs to guess at least 9 answers correctly. So

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{14,9}.(0.3)^{9}.(0.7)^{5} = 0.0066

P(X = 10) = C_{14,10}.(0.3)^{10}.(0.7)^{4} = 0.0014

P(X = 11) = C_{14,11}.(0.3)^{11}.(0.7)^{3} = 0.0002

P(X = 12) = C_{14,12}.(0.3)^{12}.(0.7)^{2} = 0.000024

P(X = 13) = C_{14,13}.(0.3)^{13}.(0.7)^{1} = 0.000002

P(X = 14) = C_{14,14}.(0.3)^{14}.(0.7)^{0} \cong 0

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.0066 + 0.0014 + 0.0002 + 0.000024 + 0.000002 = 0.0082

0.0082 = 0.82% probability that he will pass

6 0
3 years ago
A man walks at the rate of 88 paces to the minute if the average length of his paces is 0.875m, find the time take to walk 2.31k
Nataly [62]

Answer:

30 minutes

Step-by-step explanation:

Walk rate = 88 paces/ minute

Average length of pace = 0.875 m

Time taken to walk 2.31 km ;

The distance in metres :

1000 m = 1 km

2.31 km = (1000 * 2.31) = 2310 m

Recall :

Time taken = distance / speed

Distance walked in a minute = 88 * 0.875 = 77 m

Time taken = 2310 / 77

Time taken = 30 minutes

6 0
3 years ago
A simple random sample is drawn from a normally distributed population, and when making a statistical inference about the popula
DiKsa [7]
<span>To find the confidence interval, add and subtract the margin of error from the mean. With mean 18.7 and margin of error 5.9, you have 95% confidence the answer is between 12.8 and 24.6.</span>
3 0
3 years ago
Read 2 more answers
a customer buys a diiferent book that has an original selling price of $38 the books is discounted 25% the customer must pay a 6
Nimfa-mama [501]
Answer: 30.21$
Explanation:
1. 38• 0.25(25%)=28.50
2. 28.50•0.06(6)=1.71 ( the sales taxes)
3. 28.50+1.71=30.21$
Hope this helps. If it’s correct please tell me.
7 0
3 years ago
The numerator and the denominator of a fraction are thirteen and fifty, respectively. When a certain number is added to this num
Talja [164]
(13 + x)/(50 - x ) = (2/1)
Cross Multiply
2(50-x) = 1(13 + x)
100 - 2x = 13 + x
add 2x to both sides
100 -2x + 2x = 13 + x + 2x
100 = 13 + 3x
Subtract 13 from both sides
100 - 13 = 13 - 13 + 3x
87 = 3x
divide both sides by 3
29 = x

(13 + 29)/(50-29) = 42/21 = 2 to 1 ratio
7 0
3 years ago
Read 2 more answers
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