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labwork [276]
3 years ago
10

If a right triangle has a hypotenuse of length 100 units and one leg of length 60 units, what is the length of the other leg?

Mathematics
2 answers:
olchik [2.2K]3 years ago
8 0

The Pythagorean Theorem: a^2 + b^2 = c^2

a^2 = c^2 - b^2 where a and b = legs and c = hypotenuse

a^2 = 100^2 - 60^2

a^2 =10000 - 3600

a^2 = 6400

a= √6400

a = 80

Answer

The length of the other leg = 80 units

scoundrel [369]3 years ago
7 0

For this, we will be using the pythagorean theorem, which is leg^2+leg^2=hypotenuse^2 . Since we have the hypotenuse and one of the legs, we can solve for the other leg. Our equation will look like this: x^2+60^2=100^2

Firstly, solve the exponents: x^2+3600=10000

Next, subtract 3600 on both sides: x^2=6400

Next, square root both sides, and your answer will be x = 80 units

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Alex17521 [72]

[ Answer ]

\boxed{X \ = \ 114}

[ Explanation ]

\frac{x}{19} = 6

Multiply Both Sides By 19

\frac{x}{19} = 6 · 19

Simplify:

X = 114

Check Your Work:

\frac{114}{19}

Simplify:

= 6

\boxed{[ \ Eclipsed \ ]}

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