Question

WILL GIVE BRAINLIEST, THANKS, AND 5 STARS! PLEASE HELP EXPLAIN TO ME IN WORDS!

Answer 1

$\\ \rm\Rrightarrow 2x^2-7x+5=0$

• Split the middle term

$\\ \rm\Rrightarrow 2x^2-2x-5x+5=0$

• Take common

$\\ \rm\Rrightarrow 2x(x-1)-5(x-1)=0$

• Factor up

$\\ \rm\Rrightarrow (2x-5)(x-1)=0$

• Find x

$\\ \rm\Rrightarrow x=5/2,1$

Lauren written 2/5 instead of 5/2

Let's verify once more

• 2x-5=0
• 2x=5
• x=5/2

Answer 2

Answer:

So, we can check step by step.

2x^2-7x+5=0

So, 2x^2-2x-5x+5=0 is correct

2x(x-1)=2x^2-2x, 5(x-1)=-5x + 5= 0, that step is correct

(I'll skip the next step)

2x-5=0,

2x=5

x=5/2, NOT 2/5

The other one is correct

Sorry if this seems a bit vague!