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ludmilkaskok [199]
2 years ago
5

Question Find the surface area of the prism. m2

Mathematics
1 answer:
Art [367]2 years ago
5 0

Answer:

324 square meters

Step-by-step explanation:

Hey there!

The surface area of a shape is the area of all the surfaces added up

The side surface area is 48 since 16 x 3 is 48. Since there are two side areas, we need to multiply 48 x 2 is 96

Now we need to do this for the other sides

the bottom and top areas are 96 square meters each so we multiply 96 by 2 which is 192

The front and back faces have an area of 18 square meters so we multiply 18 by 2 since there are two faces which are 36

Now we add all the values: 96+192+36 which is 324

So the surface area of the prism is 324 square meters

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A pond at a hotel holds 4,290 gallons of water.
Kisachek [45]

Answer:

55 hours

Step-by-step explanation:

Write the problem as an equation.

4290-78x=0

Where 'x' is each hour the pond is being drained.

Then, solve.

4290=78x        Add 78x to each side of the equation

55=x                 Divide both sides by 78

5 0
4 years ago
WILL MARK BRAINLIEST whats 5+3
KIM [24]

Answer:

8

Step-by-step explanation:

If you have 5 apples, and Johnny gives you 3. You have 8 apples.


Hope this helps!

~COurtney

8 0
3 years ago
Read 2 more answers
Sole the problem 12 ÷ (-3)(2) + 5
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Answer:

2.6

Step-by-step explanation:

12÷ -5+5

-2.4+5

2.6

6 0
3 years ago
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Round 614,594 to the nearest ten thousand?
MrMuchimi

Answer:

610,000

Step-by-step explanation:

14,000 would be the nearest ten thousandth but its is not over 15,000 so it would round down to 10,000 making the answer 610,000.

7 0
4 years ago
The width of a container is 5 feet less than its height. Its length is 1 foot longer than its height. The volume of the containe
juin [17]

The height of container is 8 feet

<em><u>Solution:</u></em>

Let "w" be the width of container

Let "l" be the length of container

Let "h" be the height of container

The width of a container is 5 feet less than its height

Therefore,

width = height - 5

w = h - 5 ------ eqn 1

Its length is 1 foot longer than its height

length = 1 + height

l = 1 + h ---------- eqn 2

<em><u>The volume of container is given as:</u></em>

v = length \times width \times height

Given that volume of the container is 216 cubic feet

216 = l \times w \times h

Substitute eqn 1 and eqn 2 in above formula

216 = (1 + h) \times (h-5) \times h\\\\216 = (h+h^2)(h-5)\\\\216 = h^2-5h+h^3-5h^2\\\\216 = h^3-4h^2-5h\\\\h^3-4h^2-5h-216 = 0

Solve by factoring

(h-8)(h^2+4h+27) = 0

Use the zero factor principle

If ab = 0 then a = 0 or b = 0 ( or both a = 0 and b = 0)

Therefore,

h - 8 = 0\\\\h = 8

Also,

h^2+4h+27 = 0

Solve by quadratic equation formula

\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

\mathrm{For\:} a=1,\:b=4,\:c=27:\quad h=\frac{-4\pm \sqrt{4^2-4\cdot \:1\cdot \:27}}{2\cdot \:1}

h = \frac{-4+\sqrt{4^2-4\cdot \:1\cdot \:27}}{2}=\frac{-4+\sqrt{92}i}{2}

Therefore, on solving we get,

h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i

<em><u>Thus solutions of "h" are:</u></em>

h = 8

h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i

"h" cannot be a imaginary value

Thus the solution is h = 8

Thus the height of container is 8 feet

8 0
3 years ago
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