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prohojiy [21]
2 years ago
8

I'm not sure what this is can anyone lend a hand?

Mathematics
2 answers:
Irina18 [472]2 years ago
3 0

Answer:

38 minutes

Step-by-step explanation:

You have to see how long between the beginning time and ending time.

Hope this helps.

belka [17]2 years ago
3 0
38 minutes
There are 60 minutes in an hour.
At 5:34 we are 34 minutes into the hour.
60(minutes in an hour) - 34 minutes is 26.
At 6:12 we are 12 minutes into the hour.
12 + 26 = 38
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The graph below shows the function f(x)=x-3/x2-2x-3. Which statement is true?
BARSIC [14]
1. Domain.

We have x^2-2x-3 in the denominator, so:

x^2-2x-3\neq0\\\\(x^2-2x+1)-4\neq0\\\\(x-1)^2-4\neq0\\\\(x-1)^2-2^2\neq0\qquad\qquad[\text{use }a^2-b^2=(a-b)(a+b)]\\\\(x-1-2)(x-1+2)\neq0\\\\
(x-3)(x+1)\neq0\\\\\boxed{x\neq3\qquad\wedge\qquad x\neq-1}

So there is a hole or an asymptote at x = 3 and x = -1 and we know, that answer B) is wrong.

2. Asymptotes:

f(x)=\dfrac{x-3}{x^2-2x-3}=\dfrac{x-3}{(x-3)(x+1)}=\boxed{\dfrac{1}{x+1}}

We have only one asymptote at x = -1 (and hole at x = 3), thus the correct answer is A)
6 0
3 years ago
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If f(x) = x 2 + 1, find f(a + 1). a 2+ 2 a + 2 a 2 + 2 a 2+ a + 1
goblinko [34]

2a+3

Step-by-step explanation:

5 0
2 years ago
1/5 of 25 = 25 divided by 5=
vitfil [10]
5 because 25 divided by 5 is 5
5 0
3 years ago
What is the value of 12 (8 + 9)?<br> 105<br> 204<br> 357<br> 864
USPshnik [31]

Answer:

204

Step-by-step explanation:

i took the test

3 0
2 years ago
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Determine the point of intersection of right bisectors in a triangle ∆ with vertices A (-3, 5), B (1, 1) and (−7, −3). Find the
iris [78.8K]

Answer:

Point of intersection (-11/3 , 1/3)

All distances from the vertices are \frac{10\sqrt{2} }{3}

Step-by-step explanation:

The vertices of the triangle is A(-3,5) , B (1,1) and C (-7,-3)

We need to find the perpendicular bisector of the triangle first

let's take one side connecting A and B

mid point of A and B = (-1,3)

Slope of the line joining A and B = -1

slope of perpendicular to line joining A and B = 1

equation of line passing through (-1,3) with slope 1

y - 3 = 1(x-(-1))

y -3 = x+1

x-y = -4 ............(1)

similarly

mid point joining B and C = (-3,-1)

slope perpendicular to line joining B and C  =  -2

Equation of perpendicular bisector of line joining B and C =

y +1 = -2(x +3 )

y+1 = -2x -6

2x+y = -7 ..........(2)

On solving 1 and 2

x= -11/3 , y= 1/3

Distances

From A = \frac{10\sqrt{2} }{3}

From B = \frac{10\sqrt{2} }{3}

From C = \frac{10\sqrt{2} }{3}

7 0
2 years ago
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