Area=legnth times width
so multiply them together use distributive property
a(b+c)=ab+ac so
in this problem
(a+b)(c+d+e)=(a+b)(c)+(a+b)(d)+(a+b)(e)
so
x^2-2 times (2x^2-x+2)=(x^2)(2x^2-x+2)-(2)(2x^2-x+2)=(2x^4-x^3+2x^2)-(4x^2-2x+4)
add like terms
2x^4-x^3+(2x^2-4x^2)-2x+4
2x^4-x^3-2x^2-2x+4
Set up a system of equations.
l=4w
2l+2w=110
Substitute l in to the second equation.
2(4w)+2w=110
8w+2w=110
10w=110
w=11
Substitute w back into the first equation.
l=4(11)=44
So, the length is 44 feet and the width is 11 feet.
Hope this helped!
Answer:
D
Step-by-step explanation:
Tell me if i am wrong
the answer is 3/2 to this question
A = -16 b = 0 c = 541
Use the quadratic formula which is
x = [-b +- sq root (b^2 -4*a*c)] / 2*a
x = [-0 +-sq root (0 -4*-16*541)] / 2 * -16
x = + - sq root (0 -4*-16*541) / -32
x = + - sq root (34,624) / -32
x = + - 186.075 / -32
x1 = 186.075 / -32 =
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-5.81484375
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x2 = -186.075 / -32 =
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5.81484375
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