Your thoughts are correct; Ned loses 14 points overall.
The reason the correctly answered questions do not factor into the answer is because that is not what the question is asking. Correct answers are not even mentioned :)
If you are given with all the tree sides of the triangle, you may solve for all the angles through the Law of Cosines,
c² = a² + b² - 2ab(cos C)
where angle C is the angle opposite the side c. You may use the same equation to get the values of the remaining angle. Additionally, if you already have one known angle, you can solve for the rest of the angles by Law of Sines,
a / sin A = b / sin B = c / sin C
Respuesta:
25 cm²
Explicación paso a paso:
El área A de un rombo tiene:
A = pq / 2
Donde pyq son las diagonales
Tomando p como la diagonal más grande = 10 cm
Diagonal más pequeña, q = 1/2 * 10 = 5cm
Por lo tanto, el área del rombo es:
A = (10 * 5) / 2
A = 50/2
A = 25 cm²
Answer:
C. 3 in x 6 in
Step-by-step explanation:
Jammal cuts the block in a straight line parallel to one side... so the section revealed when he finishes his cut will be identical as the parallel side to which the cut is done.
We know the the left side of the prism on the image is 3 inches wide and 6 inches high... so that will also be the dimensions of the exposed cross section.
The answer is then 3 inches y 6 inches. The thickness of the block (5 inches) has no impact on the exposed area of the cross-section.