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stepan [7]
3 years ago
15

The age of a father is 2 less than 7 times the age of his son. In 3 years, the shn kf their ages will be 52. If the sons present

age is 5 years, whoch equation models this situation
Mathematics
1 answer:
creativ13 [48]3 years ago
4 0
Let x stand for father
(7*5)-2=x
(5+3)+(x+3)=52

x=33
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<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20-%20x%20-%206%20%5Cdiv%20%7Bx%7D%5E%7B2%7D%20-%204" id="TexFormula1" title="x^{2
joja [24]

\bf x^2-x-6\div x^2-4\implies \cfrac{x^2-x-6}{x^2-4}\implies \cfrac{(x-3)(x+2)}{\underset{\textit{difference of squares}}{x^2-2^2}} \\\\\\ \cfrac{(x-3)~~\begin{matrix} (x+2) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{(x-2)~~\begin{matrix} (x+2) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies \cfrac{x-3}{x-2}

8 0
4 years ago
And this one confusing me to
VikaD [51]
[6] ([3] + [50])

Just make sure you understand how to work backward with problems like this if you are ever confused. :)) good luck!!
8 0
4 years ago
Read 2 more answers
Which of the sets of ordered pairs represents a function? (5 points) A = {(3, −5), (4, 6), (−3, 9), (2, 7)} B = {(2, 4), (−1, −7
Flauer [41]

Answer: both A and b

5 0
3 years ago
Read 2 more answers
Scientists randomly select ten groups from a population of men over 50 years old. They calculate the mean weights of each of the
vfiekz [6]

Answer:

Notice that the subjects of the study are men over 50 years.

So, you need to consider that each subject is a different person with different weight and other different characteristics that determine that weight.

If we have 10 groups randomly selected, that means there's gonna be variability, otherwise, the study wouldn't make sense.

So, if each person is different, then their weights is gonna be different, giving different means.

It would be rare if both means result equal, beacuse that would mean the subjects had the same weight.

Therefore, the variability between these means can be best attributed to the variability of subjects, the difference between each person.

From a numerical perspective, the variability is attributed to the spread of the data group, that is, if there is too much difference between weights, the variabilty will increase.

8 0
4 years ago
I need assistance can I get help
DerKrebs [107]
The answer to this is 5x-8
3 0
3 years ago
Read 2 more answers
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