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Anvisha [2.4K]
2 years ago
5

In a Right Triangle, if the measurement for the base (B) equals a negative 6 and the hypotenuse equals (C) equals 12, then what

is the value of the side (A)?

Mathematics
1 answer:
katen-ka-za [31]2 years ago
8 0
Explanation:
Use pythagorean theorem: a^2+b^2=c^2
a^2+(-6)^2=(12)^2
a^2+36=144
a^2=108
a≈12.58
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3 years ago
The table shows the relationship between the cost of renting a car from the Wrecko Car Rental Company and the number of days for
Fudgin [204]

Answer:

The cost of renting the car for 20 days is $481

Step-by-step explanation:

The table of values can be formed as follows;

Day,   Cost

1,         $44

2,        $67

3,        $90

4,        $113

7,        $182

10,      $251

From the given values and the scatter plot, there is a straight line relationship between the cost and the number of days of rental of a car.

The line of best fit is therefore a straight line and from the constant increase in cost ($23) for each extra day of rental, it is possible to find the slope, m, of the data as follows;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

(x₁, y,) and (x₂, y₂) can be taken as (1, $44) and (3, $90) respectively to give;

Slope, \, m =\dfrac{90-44}{3-1} = \dfrac{46}{2} = 23 \ as \ stated \ above

The equation in slope and intercept form is therefore, y  - 44 = 23×(x - 1), which gives;

y - 44 = 23·x - 23

y = 23·x - 23 + 44 = 23·x + 21

The cost of renting the car for 20 days is then;

10×23 + 21 = $481

The cost of renting the car for 20 days = $481.

5 0
3 years ago
Helpppppppppppppppppppppppppppppppppppp
Alexxandr [17]
To take out terms outside the radical we need to divide the power of the term by the index of the radical; the quotient will be the power of the term outside the radical, and the remainder will be the power of the term inside the radical. 
First, lets factor 8:
8=2 ^{3}
Now we can divide the power of the term, 3, by the index of the radical 2:
\frac{3}{2} = 1 with a remainder of 1
Next, lets do the same for our second term x^{7}:
\frac{7}{2} = 3 with a remainder of 1
Again, lets do the same for our third term y^{8}:
\frac{8}{2} =4 with no remainder, so this term will come out completely.

Finally, lets take our terms out of the radical:
\sqrt{8x^{7} y^{8}  }= \sqrt{ 2^{3} x^{7} y^{8}   }  =2 x^{3}  y^{4}  \sqrt{2x}

We can conclude that the correct answer is the third one. 

4 0
3 years ago
Read 2 more answers
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