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ValentinkaMS [17]
3 years ago
10

Nvm i got it thanks .............

Mathematics
1 answer:
OlgaM077 [116]3 years ago
6 0

Answer:

<em>G</em><em>ood</em><em> morning</em><em> dear</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

Step-by-step explanation:

<em>Wh</em><em>at</em><em> </em><em>di</em><em>d</em><em> you</em><em> </em><em>say</em><em>?</em><em>?</em><em>?</em>

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Answer:

t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723    

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Step-by-step explanation:

Information provided

\bar X=5.97 represent the sample mean for the length

s=0.4 represent the sample standard deviation

n=93 sample size  

\mu_o =6 represent the value that we want to test

\alpha=0.05 represent the significance level

t would represent the statistic  

p_v represent the p value for the test

System of hypothesis

We need to conduct a hypothesis in order to check if the lathe is in perfect adjustment (6cm), then the system of hypothesis would be:  

Null hypothesis:\mu = 6  

Alternative hypothesis:\mu \neq 6  

since we don't know the population deviation the statistic is:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

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t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723    

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P value

The degrees of freedom are given by:

df=n-1=93-1=92  

Since is a two tailed test the p value would be:  

p_v =2*P(t_{(92)}  

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

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