Find the sum of these polynomials. (2x^2+x+3)+(3x^2+2x+1)
2 answers:
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The limit in the given graph is 3 and
is -2
Given graph of a function and we have to determine the limits when x tends to 2 minus and when x tends to 2 plus.
When we see the graph we can find that the graph is not of the linear function because it is not straight line.
From x=2 and onwards it gives values values of only -2 because it is parallel to x-axis at y=-2.From x=2 and leftwards it gives values values of only 3 because it is parallel to x-axis at y=3.
Hence the limit of the function whose graph is shown is 3 and -2.
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Easy, using 
to find the intercept:
=
=3
This is your slope. m=3
To find y=mx+b form
-4=3(-1)+b
-4=-3+b
-1=b
y=3x-1 in y=mx+b form
This is your slope. m=3
To find y=mx+b form
-4=3(-1)+b
-4=-3+b
-1=b
y=3x-1 in y=mx+b form