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4 years ago

13/15 in simplest form

Mathematics

2 answers:

Marina86 [1]4 years ago

6 0

$\frac{13}{15}=0.8666... = 0.8\overline{6}$

N76 [4]4 years ago

4 0

You can't put it in simplest form 13 can't go lower evenly

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What is the simplest form of 2 sq root 3/ sq root 6

Shkiper50 [21]

Answer:

2/√2

Step-by-step explanation:

We are to solve this surd question

2(√3)/√6

2(√3)/√2×3

2(√3)/√2×√3

Divide both by√3

2/√2

We will have to leave the answer in surd form

So the final answer is 2/√2

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3 years ago

Jason is playing a trivia game with his friends. At the end of each round, his score updates to the square of 1 less than the pr

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Answer:

8+n^2

Step-by-step explanation:

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3 years ago

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5x-3y=-11 x-2y=2 this is for home work please help

ale4655 [162]

5x - 3y = 11 ⇒ 5x - 3y = 11 ⇒ 5x - 3y = 11
x - 2y = 2 ⇒ -5(x - 3y) = 2 ⇒ -5x + 15y = 2
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3 years ago

A government report gives a 99% confidence interval for the proportion of welfare recipients who have been receiving welfare ben

juin [17]

Answer:

The estimation for the proportion for this case is $\hat p = 0.21$

And we know that the 99% confidence interval is given by:

$0.21 \pm 0.045$

So then the margin of error at 99% of confidence is 0.045, and the margin of error is given by this formula:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

If we decrease the confidence level this margin of error can't be higher than 0.045 so then the correct answer for this case would be:

d. 21% ± 4.8%

Because if the z value decrease from 2.58 to 1.96 not makes sense that the margin of error increase from 0.045(4.5%) to 0.048(4.8%)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

The estimation for the proportion for this case is $\hat p = 0.21$

And we know that the 99% confidence interval is given by:

$0.21 \pm 0.045$

So then the margin of error at 99% of confidence is 0.045, and the margin of error is given by this formula:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

If we decrease the confidence level this margin of error can't be higher than 0.045 so then the correct answer for this case would be:

d. 21% ± 4.8%

Because if the z value decrease from 2.58 to 1.96 not makes sense that the margin of error increase from 0.045(4.5%) to 0.048(4.8%)

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3 years ago

What is the value of y in this triangle?

xeze [42]

Answer: y=36 degrees

Step-by-step explanation: the exterior angle of a triangle is equal to the sum of the two remote interior angles of a triangle. using this, you can subtract 98 from 134 degrees to find your answer. 134-98 is 36 degrees. Hope this helps :)

4 0

3 years ago

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