f(x) = -3x + 6
y = -3x + 6
x = -3y + 6
x - 6 = -3y
-3 -3
⁻¹/₃x + 2 = y
⁻¹/₃x + 2 = f⁻¹(x)
g(x) = x + 2
y = x + 2
x = y + 2
x - 2 = y
x - 2 = g⁻¹(x)
Answer:
z = 4.5
Step-by-step explanation:
∠B = ∠B ∠BAD = 90° - ∠B = ∠C
ΔBAD ~ ΔBCA
AB / z = BD / AB
z = AB * AB / BD = 3*3 / 2 = 4.5
Let r = (t,t^2,t^3)
Then r' = (1, 2t, 3t^2)
General Line integral is:

The limits are 0 to 1
f(r) = 2x + 9z = 2t +9t^3
|r'| is magnitude of derivative vector


Fortunately, this simplifies nicely with a 'u' substitution.
Let u = 1+4t^2 +9t^4
du = 8t + 36t^3 dt

After integrating using power rule, replace 'u' with function for 't' and evaluate limits: