Question

Find the equation of bisector of angle betweenthe lines 7x-y+11=0 and x+y-15=0​

Answer 1

Answer:The equations of the bisectors of the angles between 3x - 4y + 7 = 0 and 12x - 5y - 8 = 0 are

3

2

+(−4)

2

3x−4y+7

=±

12

2

+(−5)

2

12x−5y−8

or

5

3x−4y+7

=±

13

12x−5y−8

or 39x−52y+91= ± (60x−25y−40)

Taking the positive sign we get 21x+27y−131=0 as one bisector

Taking the negative sign we get 99x−77y+51=0 as the other bisector

Step-by-step explanation: