Find the equation of bisector of angle betweenthe lines 7x-y+11=0 and x+y-15=0
1 answer:
Answer:The equations of the bisectors of the angles between 3x - 4y + 7 = 0 and 12x - 5y - 8 = 0 are
3
2
+(−4)
2
3x−4y+7
=±
12
2
+(−5)
2
12x−5y−8
or
5
3x−4y+7
=±
13
12x−5y−8
or 39x−52y+91= ± (60x−25y−40)
Taking the positive sign we get 21x+27y−131=0 as one bisector
Taking the negative sign we get 99x−77y+51=0 as the other bisector
Step-by-step explanation:
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16
Step-by-step explanation:
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Answer:
−49427112 us the correct answer
A represents it, since it’s on the negative side
Yes it is right that is the right one
It will be really a good answer for this 13.20
