2 years ago

Solve using the square root property.X^2=-12

Mathematics

1 answer:

Alla [95]2 years ago

5 0

Answer:

x = ± 2i $\sqrt{3}$

Step-by-step explanation:

note that $\sqrt{-1}$ = i

x² = - 12 ( take square root of both sides )

x = ± $\sqrt{-12}$ = ± $\sqrt{4(3)(-1)}$ = ± 2i $\sqrt{3}$

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Evaluate the expression for x = 2 and y = 4. Enter your answer in the box.<br><br> 16x0 + 2x2 • y –1

swat32

Given that,

The given expression is : $16x^0+2x^2{\cdot}y^{-1}$

To find,

The value of the above expression when x = 2 and y = 4

Solution,

We have,

$16x^0+2x^2{\cdot}y^{-1}$

Put x = 2 and y = 4 in the above expression.

$16x^0+2x^2{\cdot}y^{-1}\\\\=16\times (2)^0+2(2)^2\times (4)^{-1}\\\\=16\times 1+2(2)^2\times\dfrac{1}{4}\\\\=16+2\\\\=18$

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3 years ago

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Mademuasel [1]

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Step-by-step explanation:

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