The answer to your question is F(x)=20)
Answer:
1. -1.25
2. 0.1056
Step-by-step explanation:
We are given that
mean=129
S.D=0.8
1.
The z-score can be found as
z=(x-mean)/S.D
z=(128-129)/0.8
z=-1/0.8
z=-1.25
Thus, a z-score corresponding to 128 fl. Oz. milk is -1.25.
2.
We have to find P(X<128).
A z-score is already found in part 1, So,
P(X<128)=P(Z<-1.25)
P(X<128)=P(-∞<Z<0)-P(0<Z<-1.25)
Using normal area table, we get P(0<Z<-1.25)=0.3944
P(X<128)=0.5-0.3944
P(X<128)=0.1056
Thus the probability that a randomly selected jug will contain less than 128 fl. Oz. of milk is 0.1056 or 10.56%
There are total 80 dimes in the jar. B/c...
n+d=200 = n=200-d
0.05n+0.1d=$14.00
0.05(200-d)+0.1d=$14.00
10-0.05d+0.1d=$14.00
10+0.05d=$14.00
-10 -10
0.05d=$4.00
0.05d/0.05=$4.00/0.05
d=80
Answer:
i think its 1.2 not too sure though
Step-by-step explanation:
Answer:
it is a Equilateral triangle