Answer:
Y = (0, 3)
Step-by-step explanation:
Notice that the first the transformation is a rotation of 90 degrees around the origin, and then a reflection around the x axis.
If a reflection around the x axis resulted in (3, 0) that means the point was already on the x axis.
Then in order for a rotation in 90 degrees to take the point Y to (3, 0), Y must have been on the y-axis as (0, 3)
<span>Melanie had 2 1/2 bags of sand for a sandbox. The sandbox needs 3 1/4 bags of sand to fill it.
Melanie said she still needs 3/4 of a bag to fill it. Is that answer reasonable?
</span><span>
3.25 or 3 and 1/4 - 2.25 or 2 and 1/2= .75 or 3/4</span> so the answer is C.
Answer:
x
≈
16
Explanation:
Remember Sine of an angle is
opposite side
hypotenuse
So let the hypotenuse be
x
:
sin
(
47
°
)
=
opposite side
x
sin
(
47
°
)
=
12
x
To solve for
x
, divide
sin
(
47
°
)
by
12
:
x
=
12
sin
(
47
°
)
x
≈
16
To solve this problem, we must first find the fraction of action figures that Lee has gotten so far. To do this, we will represent the number of action figures that Lee currently has in the numerator divided by the denominator, the total number of action figures that Lee is attempting to collect.
First, we must recognize that Lee currently has 11 action figures plus the 3 that he got for his birthday. To find the total number of action figures that Lee has, we must add together these two parts.
11+3 = 14
Therefore, Lee has 14 action figures (this will become the numerator of the fraction). The denominator of the fraction is the total number of action figures, which we are given is 22.
Thus, our fraction is 14/22.
To convert this into a decimal, we can simply divide the numerator of the fraction by the denominator of the fraction, which gives us:
14/22 = 0.636363636
Therefore, your answer is approximately 0.636.
Hope this helps!
Answer:
Option c, A square matrix
Step-by-step explanation:
Given system of linear equations are
Now to find the type of matrix can be formed by using this system
of equations
From the given system of linear equations we can form a matrix
Let A be a matrix
A matrix can be written by
A=co-efficient of x of 1st linear equation co-efficient of y of 1st linear equation constant of 1st terms linear equation
co-efficient of x of 2st linear equation co-efficient of y of 2st linear equation constant of 2st terms linear equation
co-efficient of x of 3st linear equation co-efficient of y of 3st linear equation constant of 3st terms linear equation 
which is a matrix.
Therefore A can be written as
A= ![\left[\begin{array}{lll}3&-2&-2\\7&3&26\\-1&-11&46\end{array}\right] 3\times 3](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Blll%7D3%26-2%26-2%5C%5C7%263%2626%5C%5C-1%26-11%2646%5Cend%7Barray%7D%5Cright%5D%203%5Ctimes%203)
Matrix "A" is a 
matrix so that it has 3 rows and 3 columns
A square matrix has equal rows and equal columns
Since matrix "A" has equal rows and columns Therefore it must be a square matrix
Therefore the given system of linear equation forms a square matrix
