1 year ago

Help me to solve it.

Mathematics

1 answer:

Artemon [7]1 year ago

4 0

Answer:

That is my answer to your question

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Find the equation of the line with the giving point and slope: (4,-3), m= -1

kondaur [170]

Y+3=-x+4
y=-x+4-3
y=-x+1

8 0

2 years ago

(9, 18)and (3, n) . Find n

Maru [420]

I don't seem to comprehend what you are asking?

8 0

3 years ago

8x + 12 = 4r - 16 find r

Luda [366]

Answer:

r = 2x + 7

Step-by-step explanation:

get r on one side

8x + 12 + 16 = 4r

divide both sides by 4 to get r by itself

8x/4 + 12/4 + 16/4 = 4r/4

2x + 3 + 4 = r

2x + 7 = r

r = 2x + 7

8 0

2 years ago

which of the following represents the equation of the line with an x- intercept of 6 that passes through the point (4,4)?

luda_lava [24]

Answer:

$y=-2x+12$

Step-by-step explanation:

To write the equation of a line, find the slope between two points. Substitute two points into the slope formula. If the equation has an x-intercept of 6 then the line passes through the point (6,0). Use (6,0) and (4,4) in the formula.

$m = \frac{y_2-y_1}{x_2-x_1} =\frac{4-0}{4-6} =\frac{4}{-2} =-2$

Since m = -2, substitute its value and the point (6,0) into the point slope form. Then simplify.

$y-y_1 = m(x-x_1)\\y-0 = -2 (x-6)\\y=-2x+12$

7 0

3 years ago

The equation for a parabola has the form y = ax2 + bx + c, where a, b, and c are constants and a ≠ 0. find an equation for the p

sattari [20]

To solve the problem, substitute the given points for x in the given equation to get

$-10=(-1)^2a+(-1)b+c\Rightarrow-10=a-b+c \\ -6=(1)^2a+(1)b+c\Rightarrow-6=a+b+c \\ -13=(2)^2a+(2)b+c\Rightarrow-13=4a+2b+c$

Solving the three equations simultaneously, we have:

a = -3, b = 2 and c = -5

Therefore, the required equation is

$y=-3x^2+2x-5$

7 0

2 years ago

Help me to solve it.​

Help me to solve it.