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marin [14]
2 years ago
15

Help me to solve it.​

Mathematics
1 answer:
Artemon [7]2 years ago
4 0

Answer:

That is my answer to your question

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The length of a rectangle is 2 in longer than its width. if the perimeter of the rectangle is 44 in , find its area.
valkas [14]
P = 2(L + W)
P = 44
L = W + 2

44 = 2(W + 2 + W)
44 = 2(2W + 2)
44 = 4W + 4
44 - 4 = 4W
40 = 4W
40/4 = W
10 = W

L = W + 2
L = 10 + 2
L = 12

A = L * W
L = 12
W = 10

A = 12 * 10
A = 120 square inches <===
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