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2 years ago

Does anyone have the answers to Basic derivative rules: table on khan academy?

Mathematics

1 answer:

Paladinen [302]2 years ago

8 0

Answer:

The following table lists the value of functions ggg and hhh, and of their derivatives, g'g

′

g, prime and h'h

′

h, prime, for x=3x=3x, equals, 3.

xxx g(x)g(x)g, left parenthesis, x, right parenthesis h(x)h(x)h, left parenthesis, x, right parenthesis g'(x)g

′

(x)g, prime, left parenthesis, x, right parenthesis h'(x)h

′

(x)h, prime, left parenthesis, x, right parenthesis

333 ~~9 9space, space, 9 ~~~0 0space, space, space, 0 -15−15minus, 15 ~~~6 6space, space, space, 6

Let function GGG be defined as G(x)=2g(x)-h(x)+8G(x)=2g(x)−h(x)+8G, left parenthesis, x, right parenthesis, equals, 2, g, left parenthesis, x, right parenthesis, minus, h, left parenthesis, x, right parenthesis, plus, 8.

G'(3)=G

′

(3)=G, prime, left parenthesis, 3, right parenthesis, equals

Step-by-step explanation:

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Y = x - 4 y = 6x - 10

Citrus2011 [14]

Answer:

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Step-by-step explanation:

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3 years ago

MATH HELP!!!! WILL GIVE 5 STARS

Gnesinka [82]

Answer:

(A,C)

Step-by-step explanation:

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3 years ago

Y=3(2)^x what is the y intercept the x intercept and is the graph increasing or decreasing

TEA [102]

This is an exponential function, with base 2. Since 2 is greater than 1, the function is increasing.

For the y intercept, we have to set $x=0$ , and we have

$y=3\cdot 2^0=3\cdot 1=3$

For the x intercept, we have to set $y=0$ and solve for x:

$3\cdot 2^x=0\iff 2^x=0$

And this has no solution. All we can say is that

$\displaystyle \lim_{x\to-\infty}2^x=0$

So, the x axis is an asymptote for the function, but the graph neves crosses it.

3 0

3 years ago

Read 2 more answers

So is it just me or is my inbox getting notifications and nothing is there????

zubka84 [21]

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3 years ago

< Salir

fenix001 [56]

Answer:

Option C.

Step-by-step explanation:

Kurt started for the school at 07:35 and ends at 08:25.

Time taken by Kurt to reach the school

= 08:25 - 07:35

= (07 hours + 85 minutes) - (07 hours + 35 minutes) [Since 08 hours + 25 minutes = 07 hours + (60 + 25)minutes]

= 85 minutes - 35 minutes

= 50 minutes

Time taken by Drew to reach the school

= 08:30 - 07:55

= (07 hours + 90 minutes) - (07 hours + 55 minutes) [Since 08 hours + 30 minutes = 07 hours + (60 + 30)minutes]

= 90 minutes - 55 minutes

= 35 minutes

Difference in the time taken by Kurt and Drew = 50 - 35 = 15 minutes.

Therefore, Drew is 15 minutes faster than Kurt.

Option C. is the answer.

6 0

4 years ago