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xz_007 [3.2K]
2 years ago
15

What can you help me with on khan academy 6th grade?

Mathematics
1 answer:
WARRIOR [948]2 years ago
7 0

I could help you with math

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Write the equation of the line that passes through the point (3,5) and is perpendicular to the line y=3.
lorasvet [3.4K]

Answer:

x=3 and y=5 passes through(3,5)

x=2 and x=3 is perpendicular to y=3

so anwer is x=3

4 0
4 years ago
Need help
kow [346]

1)\\\\\dfrac{-45}{-5}=45:5=9


2)\\(-2)(4)=-8\\(2)(-4)+-8\\-16:2=-8\\-16:(-2)=8\neq-8\\\\\text{All of the following expressions have the same value except}\ -16:-2.


3)\\-3^2=-3\cdot3=-9


(-2)^4=(-2)(-2)(-2)(-2)=16\\-2^4=-(2)(2)(2)(2)=-16\neq16\\(-2)(-2)(-2)(-2)=16\\2^4=(2)(2)(2)(2)=16\\\\\text{All of the following are equivalent except}\ -2^4.

3 0
4 years ago
Solve for x.<br> Help ASAP please!!!
sattari [20]

Answer:

The value of x is 4

Step-by-step explanation:

In a right triangle, if a segment is drawn from the right angle ⊥ to the hypotenuse like the given figure, then

∵ The length of one side of the right triangle = (x + 2)

∵ The length of the hypotenuse = x + 5

∴ (x + 2)² = x (x + 5)

∵ (x + 2)² = (x + 2)(x + 2)

∴ (x + 2)(x + 2) = x(x + 5)

→ Simplify the two sides

∵ (x)(x) + (x)(2) + (2)(x) + (2)(2) = (x)(x) + (x)(5)

∴ x² + 2x + 2x + 4 = x² + 5x

→ Add the like terms in the left side

∴ x² + 4x + 4 = x² + 5x

→ Subtract x² from both sides

∵ x² - x² + 4x + 4 = x² - x² + 5x

∴ 4x + 4 = 5x

→ Subtract 4x from both sides

∴ 4x - 4x + 4 = 5x - 4x

∴ 4 = x

∴ The value of x is 4

3 0
3 years ago
Order the numbers from least to greatest -5, 18, 0, -18,9, -15 plz help asap
forsale [732]

Answer: -18, -15, -5, 0, 9, 18

7 0
3 years ago
Read 2 more answers
Use f(x) = 2x-9 and g(x)=9-x^2 to evaluate g(f(3))​
Keith_Richards [23]

Answer:

g(f(3))​ = 0

Step-by-step explanation:

f(x) = 2x - 9

f(3) = 2(3) - 9

f(3) = -3

g(-3) = 9 - (-3)^2

g(-3) = 9 - 9

g(-3) = 0

8 0
3 years ago
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