52s + 30b because 52 x s + 30 x b = 52s + 30b
Answer:
90
Step-by-step explanation:
Let the starting number be x, the two consecutive numbers after x is gonna be x+1 and x+2.
If the sum of these three numbers is 267 then:
x+(x+1)+(x+2)=267
Solve
3x+3=267
3x=267-3
3x=264
x=264/3
x=88
x+1=89
x+2=90
Your three consecutive numbers are 88, 89, and 90.
The largest one of them is 90.
You would hav to get 4% higher which Would get u to a c+
Answer:
280 ones
Step-by-step explanation:
