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adell [148]
3 years ago
9

The four hand of a clock moves from 12 to 5 o'clock through how many degrees does it move?

Mathematics
1 answer:
julsineya [31]3 years ago
8 0
To find the answer you have to first find how many degrees are there in between each number in the clock. the clock is 360°degrees and there are 12 numbers marked in a clock., so you have to divide 360 by 12 to get the number of degrees in between each number,
360°÷12=30° so there are 30°degrees between each number. 

if a clock hand moves from 12 to 5, it pass 5 numbers, so to get your final answer you have to multiply 30° by 5=150°.

so your answer is 150°degrees.
hope you can understand what i said. :)
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Answer:

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Step-by-step explanation:

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3 years ago
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snow_lady [41]

Answer:

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Step-by-step explanation:

we know that sum of angles of a traingle is 18 degrees.

given

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In a study relating the degree of warping, in mm, of a copper plate (y) to temperature in °C (x), the following summary statisti
elena-14-01-66 [18.8K]

Answer:

a)

y = 0.3035 + 0.0082x

b)

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Step-by-step explanation:

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We need to find an equation of the form

y = b + mx

where m is the slope and b the Y-intercept.

The slope m can be computed with the formula

\bf m=\displaystyle\frac{\displaystyle\sum_{i=1}^n(x_i-\bar x)(y_i-\bar y)}{\displaystyle\sum_{i=1}^n(x_i-\bar x)^2}

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\bf m=\displaystyle\frac{806.94}{98,775}=0.008169476

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\bf b=\bar y-m\bar x

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\bf b=0.5188-0.008169476*26.36=0.303452613

and the least-squares line rounded to 4 decimals would be

y = 0.3035 + 0.0082x

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We simply replace x with 40 to get

y = 0.3035 + 0.0082*40 = 0.6315 mm

c. At what temperature will we predict the warping to be 0.5 mm? Round the answer to two decimal places

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0.5 = 0.3035 + 0.0082x ===> x = (0.5-0.3035)/0.0082 ===>

 

x = 23.9634 °C

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