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maksim [4K]
3 years ago
11

Find the area and the perimeter of the shaded regions below. Give your answer as a completely simplified, exact value in terms o

f PI (no approximations). The figures are based on semicircles or quarter circles, and problems (b), (c), and (d) involve portions of a square. Calculate area and perimeter

Mathematics
1 answer:
Digiron [165]3 years ago
7 0

Check the picture below.

\stackrel{\textit{\Large Areas}}{\stackrel{triangle}{\cfrac{1}{2}(6)(6)}~~ + ~~\stackrel{semi-circle}{\cfrac{1}{2}\pi (3)^2}}\implies \boxed{18+4.5\pi} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{pythagorean~theorem}{CA^2 = AB^2 + BC^2\implies} CA=\sqrt{AB^2 + BC^2} \\\\\\ CA=\sqrt{6^2+6^2}\implies CA=\sqrt{6^2(1+1)}\implies CA=6\sqrt{2} \\\\\\ \stackrel{\textit{\Large Perimeters}}{\stackrel{triangle}{(6+6\sqrt{2})}~~ + ~~\stackrel{semi-circle}{\cfrac{1}{2}2\pi (3)}}\implies \boxed{6+6\sqrt{2}+3\pi}

notice that for the perimeter we didn't include the segment BC, because the perimeter of a figure is simply the outer borders.

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Need this ASAP please help!#2
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Answer:

The correct option is 3.

Step-by-step explanation:

From the given graph it is noticed that the related line passing through the point (-3,1) and (0,3).

If a line passing through two points, then the equation of line is

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

The equation of related line is

y-1=\frac{3-1}{0-(-3)}(x-(-3))

y-1=\frac{2}{3}(x+3)

y-1=\frac{2}{3}(x)+2

Add 1 on both the sides.

y=\frac{2}{3}(x)+2+1

y=\frac{2}{3}(x)+3

The equation of related line is y=\frac{2}{3}(x)+3.

The related line is a dotted line, it means the point on the line does not included in the solution set.

The shaded region is above the line so the sign of inequity is >.

The required inequality is

y>\frac{2}{3}(x)+3

Therefore option 3 is correct.

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Answer:

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Answer:

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Step-by-step explanation:

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