Which one you need help on?
<em>Hello There!!</em>
Let us call X the equal distances GH = HI = IJ
GH = X
HI = X
IJ = X
Note that HJ = HI + IJ, so
HJ = X + X
10 = 2X
X = 5
Well, We're looking at figure we can conclude that:
GJ + JK = GK
GJ = GH + HI + IJ
GJ = 15
GJ + JK = GK
15 + JK = 24
JK = 9
GH = X = 5
HI = X = 5
IJ = X = 5
JK = 9


From the beginning we know we are dealing with two different rates. Distance is equal to (Speed X Time). We have two different speeds though. We will call the min speed = x and the max speed = y. With those two ideas in place we can make two equations for both Tony and Rae.
Tony:
2x+3.5y=355
Rae:
2x+3y=320
Now you can solve the equations by subtracting Rae's equation from Tony's
.5y=35 solve for y and you get 70
Now plug that y value back into either equation and you can solve for x. I'll use Rae's distance:
2x+3(70)=320
x=55
Answer:
Lynn's answer 38 is correct
2(-4)^2+6
2(16)+6
32+6=38
Step-by-step explanation: