Como calculo galileo galilei el valor de la aceracion gravitacional?

maks197457 [2]

The answer is (x-5)(x-4)

5 0

3 years ago

A football team tries to move the ball forward as many yards as possible on each play, but sometimes they end up behind where th

Illusion [34]

Answer:

Given:

The distances, in yards, that a team moves on its first five plays are 2, 21, 4, 3, and 25.

Solved:

1. The greatest number is 25

2. If the moved distances are square, which one is largest?

3. The move which is greater than 4 is considered "big play"

=> 21 and 25 are big play (21 > 4, 25 > 4)

Hope this helps!

:)

3 0

3 years ago

g Annual starting salaries in a certain region of the U. S. for college graduates with an engineering major are normally distrib

algol13

Answer:

The probability that the sample mean would be at least $39000 is of 0.8665 = 86.65%.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean $39725 and standard deviation $7320.

This means that $\mu = 39725, \sigma = 7320$

Sample of 125

This means that $n = 125, s = \frac{7320}{\sqrt{125}}$

The probability that the sample mean would be at least $39000 is about?

This is 1 subtracted by the pvalue of Z when X = 39000. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{39000 - 39725}{\frac{7320}{\sqrt{125}}}$

$Z = -1.11$

$Z = -1.11$ has a pvalue of 0.1335

1 - 0.1335 = 0.8665

The probability that the sample mean would be at least $39000 is of 0.8665 = 86.65%.

4 0

2 years ago

Which system of equations can be used to find the roots of the equation 4x^2=x^3+2x?

irina [24]

Next time, please share the answer choices.
Starting from scratch, it's possible to find the roots:

<span>4x^2=x^3+2x should be rearranged in descending order by powers of x:

x^3 - 4x^2 + 2x = 0. Factoring out x: </span>x(x^2 - 4x + 2) = 0

Clearly, one root is 0. We must now find the roots of (x^2 - 4x + 2):

Here we could learn a lot by graphing. The graph of y = x^2 - 4x + 2 never touches the x-axis, which tells us that (x^2 - 4x + 2) = 0 has no real roots other than x=0. You could also apply the quadratic formula here; if you do, you'll find that the discriminant is negative, meaning that you have two complex, unequal roots.

5 0

3 years ago

Read 2 more answers

Solve for C: C-9(greater than or equal too sign)9

creativ13 [48]

Answer:

${ \tt{C - 9 \geqslant 9}} \\ \\ { \tt{C \geqslant 9 + 9}} \\ \\ { \rm{answer}} : \: { \tt{C \geqslant 18}}$

8 0

2 years ago