You have to know what x is to completely solve but you can simplify it to, 20x^-40x -23
-5 1/8 would round to -5
-9 3/4 would round to -10
1 37/41 would round to 2
-5(2)=-10
Hope this helped :)
Answer:
The probability that in a randomly selected game, the player scored between 12 and 20 points is 95%.
Step-by-step explanation:
Given information: The population mean is 16 and standard deviation is 2.
We need to find the probability that in a randomly selected game, the player scored between 12 and 20 points.
![P(12](https://tex.z-dn.net/?f=P%2812%3Cx%3C20%29)
![12=16-2(2)=\mu-2\sigma](https://tex.z-dn.net/?f=12%3D16-2%282%29%3D%5Cmu-2%5Csigma)
![20=16+2(2)=\mu+2\sigma](https://tex.z-dn.net/?f=20%3D16%2B2%282%29%3D%5Cmu%2B2%5Csigma)
So, we need to find the value of
![P(\mu-2\sigma](https://tex.z-dn.net/?f=P%28%5Cmu-2%5Csigma%3Cx%3C%5Cmu%2B2%5Csigma%29)
According to the empirical rule:
![P(\mu-\sigma](https://tex.z-dn.net/?f=P%28%5Cmu-%5Csigma%3Cx%3C%5Cmu%2B%5Csigma%29%3D68%5C%25)
![P(\mu-2\sigma](https://tex.z-dn.net/?f=P%28%5Cmu-2%5Csigma%3Cx%3C%5Cmu%2B2%5Csigma%29%3D95%5C%25)
![P(\mu-3\sigma](https://tex.z-dn.net/?f=P%28%5Cmu-3%5Csigma%3Cx%3C%5Cmu%2B3%5Csigma%29%3D99.7%5C%25)
Using the empirical rule, we get
![P(\mu-2\sigma](https://tex.z-dn.net/?f=P%28%5Cmu-2%5Csigma%3Cx%3C%5Cmu%2B2%5Csigma%29%3D95%5C%25)
![P(12](https://tex.z-dn.net/?f=P%2812%3Cx%3C20%29%3D95%5C%25)
Therefore the probability that in a randomly selected game, the player scored between 12 and 20 points is 95%.
Answer:
14x +2
Step-by-step explanation:
(8x + 6x) +3 -5 = (14x) +3-5
14x (+ 3-5) = 14x (+ 2)
Answer: the value of the diversity index D is Zero (0)
Step-by-step explanation:
Just as the meaning of diversity index is boldly explained in the question, it is the probability that randomly selected organism from a population are from a different species.
Now if the organisms are all from the same species in a population then it is impossible to select two organisms from different species.
That is, we can never select two organisms that are not from the same species.
Hence, we cant fulfil or meet the definition of diversity index .
Therefore in this situation the value of our diversity index D will be exactly zero, D = 0.