Rewrite the function as an equation.
y= 3 x −3
The slope-intercept form is y=mx + b, where m is the slope and b is the y-intercept.
y=mx + b
Find the value of m and b by using the form y = mx + b
The slope of the line is the value of m, and the y-interept is the value of b.
Slope:3
Y-intercept: -3
Answer:
whats the question
Step-by-step explanation:
Answer:

Step-by-step explanation:
Given the function
and the output
when
, we can write the equation:



We can insert the value of
into the function to verify the output equals
:



∴ We have verified that 
Hope this helps :)
Answer:
The area of the sphere in the cylinder and which locate above the xy plane is 
Step-by-step explanation:
The surface area of the sphere is:

and the cylinder
can be written as:


where;
D = domain of integration which spans between 
and;
the part of the sphere:

making z the subject of the formula, then :

Thus,


Similarly;


So;





From cylindrical coordinates; we have:

dA = rdrdθ
By applying the symmetry in the x-axis, the area of the surface will be:





![A = 2a^2 [ cos \theta + \theta ]^{\dfrac{\pi}{2} }_{0}](https://tex.z-dn.net/?f=A%20%3D%202a%5E2%20%5B%20cos%20%5Ctheta%20%2B%20%5Ctheta%20%5D%5E%7B%5Cdfrac%7B%5Cpi%7D%7B2%7D%20%7D_%7B0%7D)
![A = 2a^2 [ cos \dfrac{\pi}{2}+ \dfrac{\pi}{2} - cos (0)- (0)]](https://tex.z-dn.net/?f=A%20%3D%202a%5E2%20%5B%20cos%20%5Cdfrac%7B%5Cpi%7D%7B2%7D%2B%20%5Cdfrac%7B%5Cpi%7D%7B2%7D%20-%20cos%20%280%29-%20%280%29%5D)
![A = 2a^2 [0 + \dfrac{\pi}{2}-1+0]](https://tex.z-dn.net/?f=A%20%3D%202a%5E2%20%5B0%20%2B%20%5Cdfrac%7B%5Cpi%7D%7B2%7D-1%2B0%5D)


Therefore, the area of the sphere in the cylinder and which locate above the xy plane is 
Answer:
Step-by-step explanation:
Given:
∠C ≅ ∠E
Statements Reasons
1). ∠C ≅ ∠E 1). Given
2). ∠ABC ≅ ∠DBE 2). Vertically opposite angles
3). ΔABC ~ ΔDBE 3). By AA postulate of similarity.