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fiasKO [112]
4 years ago
7

HELP PLZ ASAP thanks!

Mathematics
1 answer:
serious [3.7K]4 years ago
4 0

Answer:

(-9, 0)

Step-by-step explanation:

Look at the point in your answer. Its y-coordinate is zero. The x-intercept is where the line intersects the x-axis. At the x-axis, every point has y-coordinate zero. Set y equal to zero and solve for x.

-2x + (1/2)y = 18

-2x + (1/2)(0) = 18

-2x = 18

x = -9

Answer: (-9, 0)

You might be interested in
R+5=3r+7 solve each equation. Combine like terms
sveta [45]
R+5=3r+7
  -5      -5
    r=3r+2
 -3r -3r
   -2r=2 
÷-2 ÷-2
r=-1

8 0
3 years ago
I need help asap first answer gets brainly
LuckyWell [14K]

Hey there! I'm happy to help!

The domain is any possible number you can input into the function to get a real output. The domain of h just means the domain of this entire function, which is called h.

Let's look at the answer options.

OPTION A

All real values of x such that x≠0.

The only way to make it so that we do not have a real output is if we get a negative square root. You cannot multiply any number by itself to get a negative number unless you use imaginary numbers, but using imaginary numbers makes our output not real.

Anyways, plugging in 0 would give us √-10, which is not a real number. That part is correct, but this option says ALL REAL NUMBERS except for 0. The problem is is that we can take any number less than ten and plug it in and we would get a negative square root, a fake number. So, this option is incorrect.

OPTION B

All real values of x such that x≥10.

Let's say we use 10 for our x and plug it in. This gives us √0, which is 0, a real output. Anything bigger than this 10 will give us a real output as well, so this option is correct.

We don't even need to check the other options because we have already found the correct answer. C,D, and E are all incorrect though because they include values less ten, which would give us a negative square root, a fake number.

I hope that this helps! Have a wonderful day!

8 0
4 years ago
#19 is the question. i’m stuck on it, i missed the class where we went over it. please help!!
vodka [1.7K]

Step-by-step explanation:

Since the powers are equal you can write the expression as a one root

But we cannot get 9 out since the square root of 9 is 3 which is second power (3^2) and the power of the root is 4

Holpe this helps, if you need further explanation you can ask.

7 0
3 years ago
Let f(x) = 3x + 2 and g(x) = 4–5x. Find f(x) + g(x)
Vadim26 [7]

Answer:

-2x + 6

Step-by-step explanation:

Step 1: Define

f(x) = 3x + 2

g(x) = 4 - 5x

Step 2: Find f(x) + g(x)

3x + 2 + 4 - 5x

-2x + 6

3 0
3 years ago
Read 2 more answers
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
ddd [48]

Answer:

f'(x) = 4x^2 - 3 for x \le -3

Step-by-step explanation:

See attachment for proper question

Given

f(x) = -\frac{1}{2}\sqrt{x + 3}

For

x \ge -3

Required

Determine the inverse function

f(x) = -\frac{1}{2}\sqrt{x + 3}

Replace f(x) with y

y = -\frac{1}{2}\sqrt{x + 3}

Swap the positions of x and y

x = -\frac{1}{2}\sqrt{y + 3}

Multiply both sides by -2

-2 * x =-2 *  -\frac{1}{2}\sqrt{y + 3}

-2x =\sqrt{y + 3}

Square both sides

(-2x)^2 =(\sqrt{y + 3})^2

4x^2 =y + 3

Make y the subject

y = 4x^2 - 3

The inverse has been solved. So, we need to replace y with f'(x)

f'(x) = 4x^2 - 3

Next, is to determine the interval

x \ge -3

Change inequality to \le

x \le -3

Hence, the inverse function is:

f'(x) = 4x^2 - 3 for x \le -3

7 0
3 years ago
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