Answer:
Find the answers below
Step-by-step explanation:
Using m<X as the reference angle
Opposite YZ = 7
Adjacent XY = 10
Hypotenuse XZ = √149
Using the SOH CAH TOA identity
sinX = opp/hyp
sinX =YZ/XZ
sinX = 7/√149
For cos X
cos X = adj/hyp
cos X =10/√149
Using m<Z as reference angle;
Opposite XY = 10
Adjacent YZ = 7
Hypotenuse XZ = √149
Using the SOH CAH TOA identity
sinZ = opp/hyp
sinZ =10/√149
sinZ = 7/√149
For cos Z
cosZ = 7/√149
Answer:
line
x-intercept | 0
f-intercept | 0
normal vector | (-3072/sqrt(9437185), 1/sqrt(9437185))≈(-1., 0.000325521)
slope | 3072
curvature | 0
Step-by-step explanation:
Hi sam, do you want to know the answer? Try using a protractor, you will see the degree is 125, its like a obtuse angle
Answer:
It decreased
Step-by-step explanation:
It decreased. Assuming that the temperature is 100 and it is now reduced by 60% then the temperature will be at 40 and if it increased by 80% then the final temp is 72. So it is 48% of the original temp.
139,000,000 over 1, any number is a fraction just put it over 1