The answer is C. I got this by doing a^2 + b^2= c^2. 50^2 + 16^2=c^2, 2500 + 256 = c^2, 2756 = c^2, then you take the square root of 2756 and that gives you your answer 52.50 yards. Hope this helps :D
A. To be able to have the 2 sides ( the 2 triangles) line up correctly, Net A would be the correct one.
B. AB = 3
BC = 5
CD = 9.4
C. Surface area:
9.4 x 5 = 47
9.4 x 3 = 28.2
9.4 x 4 = 37.6
3 x 4 = 12
Total: 47 + 28.2 + 37.6 + 12 = 124.8 sq. in.
9514 1404 393
Answer:
38.5°
Step-by-step explanation:
A triangle solver can give an answer easily. The angle is 38.5°.
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The law of cosines can be written to solve for an unknown angle C opposite side 'c' and flanked by sides 'a' and 'b'.
C = arccos((a² +b² -c²)/(2ab))
Here, we have a=35, b=48, c=30, so the angle is ...
C = arccos((35² +48² -30²)/(2·35·48)) = arccos(2629/3360) ≈ 38.515°
The angle the cable makes with the pole is about 38.5°.
Answer: 4,5
Step-by-step explanation:
D. You can find a perpendicular line by finding the inverse equations (-(1/)2 x+3