There is only one product in a synthesis reaction.
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The number of atoms present in 0.58 mole of magnesium, Mg is 3.49×10²³ atoms
<h3>Avogadro's hypothesis </h3>
1 mole of Mg = 6.02×10²³ atoms
<h3>How to determine the atoms in 0.58 mole of Mg </h3>
1 mole of Mg = 6.02×10²³ atoms
Therefore,
0.58 mole of Mg = 0.58 × 6.02×10²³
0.58 mole of Mg = 3.49×10²³ atoms
Thus, 3.49×10²³ atoms are present in 0.58 mole of Mg
Learn more about Avogadro's number:
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Answer:
1.28 × 10²² atoms
Step-by-step explanation:
A common formula for determining the amount of sample remaining (N) in terms of its half-life (t_½) is
N =N₀(½)ⁿ
where n is the number of half-lives
n = t/t_½
=====
Data:
N₀ = 6.02 × 10²³ atoms
t = 20 da
t_½ = 3.6 da
=====
The calculation:
N₀ =6.02 × 10²³ atoms
n = 20/3.6
n= 5.56
N = 6.02 × 10²³ × (½)^5.56
N = 6.02 × 10²³ × 0.0212
N = 1.28 × 10²² atoms