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2 years ago

Which of the following means greater than or equal to?

Mathematics

1 answer:

Arada [10]2 years ago

6 0

Answer:

at least

Step-by-step explanation:

i don't know how to fully explain it, but by saying "atleast x" you're saying the minimum value it can be will be x. Maximum means it will not exceed that number, along with "not greater than" and "at most"

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For a hypothesis test of H0: p = 0.65 against the alternative Ha: p < 0.65, the z test statistic is found to be -2.35. What c

worty [1.4K]

Answer:

The finding is significant at both α = 0.05 and α = 0.01.

Step-by-step explanation:

Given that:

Null hypothesis : H0: p = 0.65 against the Alternative Ha: p < 0.65,

The test statistic ; z test = - 2.35

From the test statistic value, we can obtain the p value of the test :

To determine if the claim is significant at both α = 0.05 and α = 0.01

We compare the Zstatistic and Zcritical values

If Zstatistic < Zcritical ; then we reject H0; if otherwise, we fail to reject H0

Zcritical at 95% one tailed = - 1.645 (left tail)

Zcritical at 95% one tailed = -2.326 (left tail)

- 2.35 < - 1.645

-2. 35 < 2.326

Since, Zstatistic < Zcritical;

The finding is significant at both α = 0.05 and α = 0.01.

7 0

2 years ago

Determine whether each pair of lines are parallel, perpendicular, or neither. line n: y = -2x-4 line m: y = -2x+8

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6 0

3 years ago

A factory received a shipment of 11 hammers, and the vendor who sold the items knows there are 2 hammers in the shipment that ar

zhenek [66]

Question:

If a sample of 2 hammer is selected

(a) find the probability that all in the sample are defective.

(b) find the probability that none in the sample are defective.

Answer:

a $Pr = \frac{2}{110}$

b $Pr = \frac{72}{110}$

Step-by-step explanation:

Given

$n = 11$ --- hammers

$r = 2$ --- selection

This will be treated as selection without replacement. So, 1 will be subtracted from subsequent probabilities

Solving (a): Probability that both selection are defective.

For two selections, the probability that all are defective is:

$Pr = P(D) * P(D)$

$Pr = \frac{2}{11} * \frac{2-1}{11-1}$

$Pr = \frac{2}{11} * \frac{1}{10}$

$Pr = \frac{2}{110}$

Solving (b): Probability that none are defective.

The probability that a selection is not defective is:

$P(D') = \frac{9}{11}$

For two selections, the probability that all are not defective is:

$Pr = P(D') * P(D')$

$Pr = \frac{9}{11} * \frac{9-1}{11-1}$

$Pr = \frac{9}{11} * \frac{8}{10}$

$Pr = \frac{72}{110}$

8 0

3 years ago

Solve for x: 1 over 3 (2x − 8) = 4. (1 point)

garik1379 [7]

Answer:

x=6

Step-by-step explanation:

$2x - 8 = 4 \\ 2x = 4 + 8 \\ 2x = 12 \\ x = \frac{12}{2} \\ x = 6$

6 0

2 years ago

I have been stuck on this forever plz help <br> What is the surface area of this cylinder

Andrei [34K]

Answer:

1865.16 m^2

Step-by-step explanation:

first let 's find radius of a circle

radius=diameter/2

=18/2

=9 m

area of a cylinder=2πrh+2πr2

=2*3.14*9*24 + 2*3.14*(9)^2

=1356.48 + 2*3.14*81

=1356.48 + 508.68

=1865.16 m^2

6 0

2 years ago

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