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sergejj [24]
2 years ago
7

Which of the following lines are parallel?

Mathematics
1 answer:
borishaifa [10]2 years ago
7 0

Answer:

D&E, A&B

Step-by-step explanation:

It's pretty confusing but I know any of the answers with "c" in it is incorrect. The other options seem correct.

You might be interested in
What is the volume of a cylinder with base radius 333 and height 888?
ozzi

Answer:

V≈3.09×108

Step-by-step explanation:

Shape: Cylinder

Solved for volume

Radius: 333

Height: 888

Formula: Radius, Height

Exact answer: V≈3.09×108

<u><em>Hope this helps.</em></u>

4 0
3 years ago
The quality-control department of Starr Communications, the manufacturer of video-game cartridges, has determined from records t
notsponge [240]

Answer: (A) The probability that a cartridge purchased will have a video or audio defect is 1.9%

(B) The probability that a cartridge purchased will not have a video or audio defect is zero.

Step-by-step explanation: The data given shows that 1.2% (or 120) cartridges have video defects, 0.9% have audio defects (or 90) and 0.2% (or 20) have both audio and video defects.

The possible outcomes for all events (audio defects and video defects) is derived as 120 plus 90 which is equals 210 possibilities (or possible outcomes).

Therefore the probability of having an audio defect is calculated as follows;

P(Audio) = Number of required outcomes/Number of all possible outcomes

P(Audio) = 90/210

P(Audio) = 3/7

Also the probability of having a video defect is derived as follows;

P(Video) = Number of required outcomes/Number of all possible outcomes

P(Video) = 120/210

P(Video) = 4/7

However we should take note of the fact that 0.2% or 20 of the cartridges in the sample size has both audio and video defects. Hence the probability that a cartridge has both audio and video defects is calculated as;

P(Audio and Video) = Number of required outcomes/Number of all possible outcomes

P(Audio and Video) = 20/210

P(Audio and Video) = 2/21

To calculate the probability that a cartridge bought would have either an audio or a video defect would mean to add both probabilities together, but we MUST SUBTRACT the probability of having both an audio defect and video defect (that is P{Audio and Video}). The reason is that this is already included in both probabilities and we need to avoid double counting. Hence we have;

(A); P(Video OR Audio defect) = P(Audio) + P(Video) - P(Audio and Video)

P(Video OR Audio defect) = (3/7 + 4/7) - 2/21

P(Video OR Audio defect) = 1 - 2/21

P((Video OR Audio defect) = 19/21

Therefore the probability that a cartridge purchased will have a video or audio defect is 190, or better still 1.9%.

(B): From all possibilities shown, which is 210 possibilities of either events, we have determined that 120 will be the probability of having an audio defect and 90 will be the probability of having a video defect. Therefore the probability that a cartridge purchased will not fall into any of either possibilities is zero.

6 0
3 years ago
Help pls please PLEASE​
horsena [70]

Answer:

c

Step-by-step explanation:

it's really product of power

7 0
2 years ago
One pound of chicken costs $3.Jim buys 8 and 2/3 pounds of chicken.how much does jim pay for the chicken?
FromTheMoon [43]
It would cost $26 because 3x8=24. 3/1/3=1. so 1/3=$1.
7 0
3 years ago
3.
Zanzabum

Answer: What is the top selling board game.

Step-by-step explanation: It is the only one that uses statistics to show the top selling game.

4 0
3 years ago
Read 2 more answers
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