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2 years ago

This will be the last prob for today but thx soo much for helping

Mathematics

1 answer:

____ [38]2 years ago

8 0

Answer:

Step-by-step explanation:

If you simplify you get 0 = 19/3, which is false. So there is no solution.

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Explain when a relation is also a function

nordsb [41]

Answer:

A relation is a function if the x-values map to only one y-value. In other words, if a relation is one-to-one or many-to-one it is a function.

Step-by-step explanation:

4 0

2 years ago

The ratio of vowels to Constance to a paragraph is 3:5 there are 280 letters in the paragraph how many are vowels how many are c

Bas_tet [7]

Answer:

280/8 = 35 "sets"

35*3 = 105 Constance

35*5 = 175 vowels

Step-by-step explanation:

8 0

2 years ago

PLSS HELP ME WITH THIS! 20 POINTS

Svetradugi [14.3K]

Answer:

Step-by-step explanation:

Every $x$ is 6 times bigger than $y$

3 0

1 year ago

Read 2 more answers

A lab technician made a 14 cm diameter hole through the middle of a cylinder that has a diameter of 20 cm and a height of 28 cm.

Step2247 [10]

Answer:

The volume of the finished cylinder is $4486.2 m^3$

Step-by-step explanation:

To find the volume of the finished cylinder, we have to first find the volume of the hole (with 14 cm diameter and a height of 28 cm) and subtract it from the volume of the original cylinder (with diameter of 20 cm and a height of 28 cm).

Note: The hole is also cylindrical in shape.

The volume of a cylinder is given as:

$V = \pi r^2h$

where r = radius, h = height

VOLUME OF THE HOLE

The diameter of the hole is 14 cm, hence, its radius is 7 cm (14 / 2 = 7)

Its volume is:

$V = \pi *7^2 * 28\\V = 4310.3 m^3$

VOLUME OF THE ORIGINAL CYLINDER

The diameter of the cylinder is 20 cm, hence, its radius is 10 cm (20 / 2 = 10)

Its volume is:

$V = \pi *10^2 * 28\\V = 8796.5 m^3$

Hence, the volume of the finished cylinder will be:

$8796.5 - 4310.3 = 4486.2 m^3$

The volume of the finished cylinder is $4486.2 m^3$

8 0

2 years ago

If f(x)=x-1/3 and g(x)=3x+1, what is (f o g)(x)?

BlackZzzverrR [31]

Answer:

$3x+\frac{2}{3}$

Step-by-step explanation:

$f(x)=x-\frac{1}{3}$

$g(x)=3x+1$

Hence, $(f o g)(x)=f(3x+1)$

But, $f(3x+1)=(3x+1)-\frac{1}{3}$

Simplifying,

$f(3x+1)=3x+(1-\frac{1}{3})$

= $f(3x+1)=3x+(\frac{3-1}{3})$

= $f(3x+1)=3x+(\frac{2}{3})$

Hence, $(f o g)(x)=3x+(\frac{2}{3})$

8 0

2 years ago

This will be the last prob for today but thx soo much for helping​

This will be the last prob for today but thx soo much for helping