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frez [133]
3 years ago
10

Kinda confusing problem given by my teacher:

Mathematics
1 answer:
Allisa [31]3 years ago
8 0

Answer:

Below

Step-by-step explanation:

281.6x20%= 56.32

281.6+56.31=337.91

337.91x12%=40.55

337.91+40.55=378.46

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Please see the photo. It's not 4 or 6.
Verdich [7]

Answer:

x = 9

Step-by-step explanation:

The product of the external part and the entire part of one secant is equal to the product of the external part and the entire part of the other secant, that is

5(x - 6 + 5) = 4(x - 3 + 4)

5(x - 1) = 4(x + 1) ← distribute parenthesis on both sides

5x - 5 = 4x + 4 ( subtract 4x from both sides )

x - 5 = 4 ( add 5 to both sides )

x = 9

4 0
3 years ago
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PLEASE HELP ITS TIMED LITTERALY IM BEGGING :(( 32 points WITH BRAINLIEST!!
Volgvan

Answer:

I think it might be C but I'm not 100% sure!

Step-by-step explanation:

You have to find a line of best fit (a line through the dots) but it's kind of tricky to do that so I think it's probably C but it could also be A. Just use your best judgement on this one!

4 0
3 years ago
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If you gain 7 dollars every 65 second how long will it take to get 50000 dollars
Vlada [557]

Answer:

5 days

(the exact number of days below)

Step-by-step explanation:

65/7=9.28571429

9.28571429 sec = 1 dollar

464285.715 seconds=50000 dollars

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4 0
2 years ago
What is 88% of 250? I really need help with this!
Aneli [31]
220 .............................
8 0
4 years ago
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A dairy company gets milk from two dairies and then blends the milk to get the desired amount of butterfat. Milk from dairy I co
zubka84 [21]

Answer:

a) i The company should buy 40 gallons from dairy I and 60 gallons from dairy

ii) What is the maximum amount of​ butterfat? The total amount of butterfat from Diary I and Diary II = 3.12% + 1.93%

=5.05%

b.The excess capacity of dairy I is 10 ​gallons, and for dairy II it is 30 gallons.

Step-by-step explanation:

a. How much milk from each supplier should the company buy to get at most 100 gallons of milk with the maximum amount of​ butterfat?

From the question, we are told that:

Milk from dairy I costs ​$2.40 per​ gallon, Milk from dairy II costs ​$0.80 per gallon.

Let's represent:

Number of gallons of Milk from dairy I = x

Number of gallons of Milk from dairy II = y

At most ​$144 is available for purchasing milk.

$2.40 × x + $0.80 × y = 144

2.40x + 0.80y = 144........ Equation 1

x + y = 100....... Equation 2

x = 100 - y

2.40(100 - y) + 0.80y = 144

240 - 2.4y + 0.80y = 144

-1.60y = 144 - 240

-1.6y = -96

y = -96/-1.6

y = 60

From Equation 2

x + y = 100....... Equation 2

x + 60 = 100

x = 100 - 60

x = 40

Therefore, since number of gallons of Milk from dairy I = x and number of gallons of Milk from dairy II = y

The company should buy 40 gallons from dairy I and 60 gallons from dairy

II. What is the maximum amount of​ butterfat?

From the question

Dairy I can supply at most 50 gallons averaging 3.9​% ​butterfat,

50 gallons = 3.9% butterfat

40 gallons =

Cross Multiply

= 40 × 3.9/50

= 3.12%

Dairy II can supply at most 90 gallons averaging 2.9​% butterfat.

90 gallons of milk = 2.9% butter fat

60 gallons of milk =

Cross Multiply

= 60 × 2.9%/90

=1.9333333333%

≈ 1.93%

The total amount of butterfat from Diary I and Diary II = 3.12% + 1.93%

=5.05%

b. The solution from part a leaves both dairy I and dairy II with excess capacity. Calculate the amount of additional milk each dairy could produce.

Excess capacity of Diary I =

50 gallons - 40 gallons = 10 gallons

Excess capacity of Diary II =

90 gallons - 60 gallons = 30 gallons

Therefore, the excess capacity of dairy I is 10 ​gallons, and for dairy II it is 30 gallons.

3 0
3 years ago
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