The table is an exponential function, and the equation that represents this function is
The table is given as:
x F(x)
4 15
5 31
7 127
8 255
Rewrite the table as:
x F(x)
4 16 - 1
5 32 - 1
7 128 - 1
8 256 - 1
Express as a base of 2
x F(x)
4 2⁴ - 1
5 2⁵- 1
7 2⁷ - 1
8 2⁸ - 1
Notice that the function is 1 subtracted from 2 raised to the power of the input.
This is represented as:
Hence, the equation of the table is
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Answer:
The test is not significant at 5% level of significance, hence we conclude that there's no variation among the discussion sections.
Step-by-step explanation:
Assumptions:
1. The sampling from the different discussion sections was independent and random.
2. The populations are normal with means and constant variance
There's no variation among the discussion sections
There's variation among the discussion sections
Df Sum Sq Mean sq F value Pr(>F)
Section 7 525.01 75 1.87 0.99986
Residuals 189 7584.11 40.13
Test Statistic =
Since our p-value is greater than our level of significance (0.05), we do not reject the null hypothesis and conclude that there's no significant variation among the eight discussion sections.