Answer:
The solution code is written in Python 3.
- def convertDate(date_string):
-
- date_list = date_string.split("/")
-
- for i in range(0, len(date_list)):
- date_list[i] = int(date_list[i])
-
- return date_list
-
-
- print(convertDate('06/11/1930'))
Explanation:
Firstly, create a function convertDate() with one parameter, <em>date_string</em>. (Line 1).
Next, use the Python string <em>split()</em> method to split the date string into a list of date components (month, day & year) and assign it to variable <em>date_list</em>. (Line 3) In this case, we use "/" as the separator.
However, all the separated date components in the <em>date_list</em> are still a string. We can use for-loop to traverse through each of the element within the list and convert each of them to integer using Python<em> int() </em>function. (Line 5 - 6)
At last return the final date_list as the output (Line 8)
We can test our function as in Line 11. We shall see the output is as follow:
[6, 11, 1930]
def dx(fn, x, delta=0.001):
return (fn(x+delta) - fn(x))/delta
def solve(fn, value, x=0.5, maxtries=1000, maxerr=0.00001):
for tries in xrange(maxtries):
err = fn(x) - value
if abs(err) < maxerr:
return x
slope = dx(fn, x)
x -= err/slope
raise ValueError('no solution found')
Answer:
Explanation:
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Explanation:
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