Calculate the constant difference 1,2,3

Mathematics

1 answer:

Oxana [17]3 years ago

7 0

Step-by-step explanation:

Seeing its an arithmetic sequence

T1=1......T2=2.....T3=3

To get your constant difference

T2=T1 is also equals to T3=T2

so 3-2=1 and 2-1=1

therefore the constant difference is 1

You might be interested in

How would you use a number line to put integers in order from least to greatest?

oksian1 [2.3K]

C.Graph the absolute values of the integers,then read them from left to right.

8 0

4 years ago

Ed is 7 years older than Ted. Ed’s age is also 3/4 times Ted’s age. How old are Ed and Ted?

svetlana [45]

Let Ted be x.

Ed is 7 years older = x + 7

Ed = (3/4)Ted

(x + 7) = (3/4)x

x + 7 = 3x/4

x - 3x/4 = -7

x/4 = -7

x = -28, Ted = -28 years.

(x + 7) = -28 + 7 = -21, Ed = -21 years

Goodness. We had negative numbers for the ages, well does that make sense? No it doesn't.

Our answer is correct. But the sense in the question is lacking. The question has been wrongly set.

<span>We might assume negative ages to mean before they came into the world, before birth! </span>

7 0

4 years ago

What math symbol is this? <br> Σ

omeli [17]

Answer:

summation

Step-by-step explanation:

This symbol is the summation symbol

It means to sum what comes after it

3 0

3 years ago

Read 2 more answers

A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 2

Shalnov [3]

Answer:

The expected winnings for a person buying 1 ticket is -0.2.

Step-by-step explanation:

Given : A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 25 cents each, find the expected winnings for a person buying 1 ticket.

To find : What are the expected winnings?

Solution :

There are one first prize, 2 second prize and 20 third prizes.

Probability of getting first prize is $\frac{1}{20000}$