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3 years ago

PLEASE HELP FAST

Mathematics

2 answers:

statuscvo [17]3 years ago

6 0

Answer:

i dont see an image

Step-by-step explanation:

Ket [755]3 years ago

5 0

Answer:

504in3 (cubed)

Step-by-step explanation:

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Brainliest please help! A storage bin is a rectangular prism. Its volume is 300 cm cubed.

melisa1 [442]

Answer:

∛50 cm, 2∛50 cm, 3∛50 cm

Step-by-step explanation:

V= wlh

V=300 cm³

w= 1/3l

h= 2/3l

---------

l*1/3l*2/3l=300
2/9l³=300
l³= 1350
l= ∛1350= 3∛50 cm
w= 1/3*3∛50= ∛50 cm
h= 2/3*3∛50= 2∛50 cm

6 0

3 years ago

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Solve the system substitution y= 4x + 1 and 3x+2y =13

strojnjashka [21]

Given :

${\qquad \sf \dashrightarrow y= 4x + 1 \: –––– \sf \: (i)}$

${\qquad \sf \dashrightarrow 3x + 2y = 13 \: –––– \sf \: (ii)}$

Now, Substituing the value of y in equation (ii) :

${\qquad \sf \dashrightarrow \: 3x + 2y = 13 }$

${\qquad \sf \dashrightarrow \: 3x + 2(4x + 1) = 13 }$

${\qquad \sf \dashrightarrow \: 3x + 8x + 2 = 13 }$

${\qquad \sf \dashrightarrow \: 11x + 2 = 13 }$

${\qquad \sf \dashrightarrow \: 11x = 13 - 2 }$

${\qquad \sf \dashrightarrow \: 11x = 11 }$

${\qquad \sf \dashrightarrow \: x = \dfrac{11}{11} }$

${\qquad \sf \dashrightarrow \bf \: x = 1 }$

Now, substituting the value of x in equation (i) :

${\qquad \sf \dashrightarrow y= 4x + 1}$

${\qquad \sf \dashrightarrow y= 4(1) + 1}$

${\qquad \sf \dashrightarrow y= 4 + 1}$

${\qquad \bf \dashrightarrow y= 5}$

8 0

2 years ago

At Palermo Pizzeria pizzas are sold by their diameter. Rihanna orders a 14-inch pizza. Which is closest to the area of the piz

Yuliya22 [10]

To get the Area you need the Radius to get the Radius you need to divide 14 by 2 14/2=7

The Radius is 7 now to get the area we need to multiply 7 by 7 but also add pi 3.14

7*7*3.14=153.86

4 0

3 years ago

Simplify<br><br> sqrt(3 + 2 sqrt 2) ...?

trasher [3.6K]

The answer is 1 + √2

sqrt(2) is $\sqrt{2}$
sqrt(3 + 2 sqrt 2) is $\sqrt{3 +2 \sqrt{2} }$
Now, let's simplify $\sqrt{3 +2 \sqrt{2} }$ .
We will use square of sum: (a + b)² = a² + 2ab + b²

$\sqrt{3 +2 \sqrt{2} } = \sqrt{1+2+2 \sqrt{2} }= \sqrt{1+2 \sqrt{2}+2 }= \\ 
= \sqrt{1^{2} +2*1* \sqrt{2} + (\sqrt{2} ) ^{2} } = \sqrt{(1+ \sqrt{2}) ^{2}} =1+ \sqrt{2}$

8 0

3 years ago

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PLEASE HELP ME<br> Factor each expression,<br> 2n^(2)+ 3n -2

kotegsom [21]

I would suggest factoring using the grouping method. The answer I got was (2n-1)(n+2)

5 0

4 years ago